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elena-s [515]
3 years ago
6

Find the value of x. B X+5 4 D E 2x 3 А x = [?]

Mathematics
1 answer:
Greeley [361]3 years ago
5 0

Answer:

x = 3

Step-by-step explanation:

Δ BDE and Δ BAC are similar triangles, thus the ratio of corresponding sides are equal, that is

\frac{BD}{BA} = \frac{BE}{BC}, substitute values

\frac{x+5}{3x+5} = \frac{4}{7} ( cross- multiply )

4(3x + 5) = 7(x + 5) ← distribute parenthesis on both sides )

12x + 20 = 7x + 35 ( subtract 7x from both sides )

5x + 20 = 35 ( subtract 20 from both sides )

5x = 15 ( divide both sides by 5 )

x = 3

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If a number has 2 and 6 as factors then it has 12 as a factor
zhuklara [117]

Answer:

yes

Step-by-step explanation:

2,4,6,8,10,12 so on

6 0
3 years ago
Read 2 more answers
Grace wove a potholder with an area of 80 square inches. The lengths and widths of the sides are whole numbers. Which dimensions
docker41 [41]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the question :

Grace wove a potholder with an area of 80 square inches. The lengths and widths of the sides are whole numbers. Which dimensions make the most sense for a potholder?

Since the Area of the potholder = 80 sq inch

And the dimension of the potholder ; length and width are integers ; Hence, possible dimensions could be ;

Area = length × width

80 = length × width

(80, 1), (40, 2), (20, 4), (10, 8), (16, 5)

Potholders are fabrics sewn from the purpose of being used to handle pots and other kitchen equipments.

Usually the dimension are usually close, hence, the most sensible dimension a potholder with an area of 80 sq inch could have is 8 by 10 or vice-versa.

7 0
3 years ago
if you purchase 5 shirt whitch are on sale for 17.98$ each write a expression for the total cost if the shirts
OLga [1]
5•17.98=89.9

$89.9 is needed
8 0
3 years ago
Read 2 more answers
(x^(2)-11x+30)/(x^(2)-25)*(x^(2)+6x+5)/(x-5x-6) simplify the rational expression
DanielleElmas [232]
Simplify the following:
((x^2 - 11 x + 30) (x^2 + 6 x + 5))/((x^2 - 25) (x - 5 x - 6))

The factors of 5 that sum to 6 are 5 and 1. So, x^2 + 6 x + 5 = (x + 5) (x + 1):
((x + 5) (x + 1) (x^2 - 11 x + 30))/((x^2 - 25) (x - 5 x - 6))

The factors of 30 that sum to -11 are -5 and -6. So, x^2 - 11 x + 30 = (x - 5) (x - 6):
((x - 5) (x - 6) (x + 5) (x + 1))/((x^2 - 25) (x - 5 x - 6))

x - 5 x = -4 x:
((x - 5) (x - 6) (x + 5) (x + 1))/((x^2 - 25) (-4 x - 6))

Factor -2 out of -4 x - 6:
((x - 5) (x - 6) (x + 5) (x + 1))/(-2 (2 x + 3) (x^2 - 25))

x^2 - 25 = x^2 - 5^2:
((x - 5) (x - 6) (x + 5) (x + 1))/(-2 (x^2 - 5^2) (2 x + 3))

Factor the difference of two squares. x^2 - 5^2 = (x - 5) (x + 5):
((x - 5) (x - 6) (x + 5) (x + 1))/(-2(x - 5) (x + 5) (2 x + 3))

((x - 5) (x - 6) (x + 5) (x + 1))/((x - 5) (x + 5) (-2) (2 x + 3)) = ((x - 5) (x + 5))/((x - 5) (x + 5))×((x - 6) (x + 1))/(-2 (2 x + 3)) = ((x - 6) (x + 1))/(-2 (2 x + 3)):
((x - 6) (x + 1))/(-2 (2 x + 3))

Multiply numerator and denominator of ((x - 6) (x + 1))/(-2 (2 x + 3)) by -1:

Answer: (-(x - 6) (x + 1))/(2 (2 x + 3))
4 0
3 years ago
PLEASE HELP ALGEBRA WORK
g100num [7]
I believe it is A

Hope this answer helps
3 0
3 years ago
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