Answer:
1600 integers
Step-by-step explanation:
Since we have a four digit number, there are four digit placements.
For the first digit, since there can either be a 5 or an 8, we have the arrangement as ²P₁ = 2 ways.
For the second digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.
For the third digit, since it neither be a 5 or an 8, we have two less digit from the total of ten digits which is 10 - 2 = 8. So, the number of ways of arranging that is ⁸P₁ = 8.
For the last digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.
So, the number of integers that can be formed are 2 × 10 × 8 × 10 = 20 × 80 = 1600 integers
To get that, you have to multiply the both numbers, which is 24*12=288
Answer:217.00
Step-by-step explanation:
Answer:
5^-4
1 / 5^4
Step-by-step explanation:
5^3 / 5^7
We know a^b / a^c = a^(b-c)
5^(3-7)
5^-4
If you are not allowed to have negative exponents
We know a^-b = 1/a^b
1 / 5^4