Answer: the domain of f/g is every real number except 1 which can be conventionally expressed as {(x,y): <em>x</em> ∈ R, x ≠ 1} OR (-∞ ≤ x < 1) ∩ (1< x ≤ ∞) OR x ∈ R; x ≠ 1.
Step-by-step explanation:
since f(x) = x + 4 and g(x) = x - 1
then f/g = x + 4/x - 1
the denominator of a function cannot be zero since a fraction with a denominator of zero is undefined.
∴ x - 1 ≠ 0
the value of x when g(x) = 0 is
x - 1 = 0
x = 1
∴ x ≠ 1
Therefore the domain of f/g is every real number except 1 which can be conventionally expressed as {(x,y): <em>x</em> ∈ R, x ≠ 1} OR (-∞ ≤ x < 1) ∩ (1< x ≤ ∞) OR x ∈ R; x ≠ 1.
<h2>1.</h2><h3>1)</h3>
Put the given values of p and q in the factored form equation.
... f(x) = (x -(-1))(x -(-2)) . . . . p and q values put in
... f(x) = (x +1)(x +2) . . . . . . .simplified
<h3>2)</h3>
Multiplying the factors, we have
... f(x) = x(x +2) + 1(x +2) = x² +2x +1x +2
... f(x) = x² +3x +2
<h2>2.</h2>
We want to factor x³ -x² -6x. We notice first of all that x is a factor of all terms. Thus we have
... = x(x² -x -6)
Now, we're looking for factors of -6 that add up to -1. Those are -3 and 2. Thus the factorization is ...
... = x(x -3)(x +2)
<h2>3.</h2>
We want a description of the structure and an equivalent expression for
... 64x⁹ -216
We note that 64, 216, and x⁹ are all cubes, so this expression is ...
... the difference of cubes.
It can be rewritten to
... = 8((2x³)³ -3³)
and so can be factored as
... = 8(2x³ -3)(4x⁶ +6x³ +9)
so we know that each m&m weighs about 2g.
the next line says to write a direct variation equation.
(definition: mathematical relationship between two variables that can be expressed by an equation in which one variable is equal to a constant times the other)
we then make the equation ( w=xm), then we use that equation to figure out the next line, which is to find the amount of m&ms that would fit in a bag of 1000.
(my head cant really process part a cause of a recent headache, so sorry if its wrong)
the answer to part b would be 500, which you can provide evidence based off of your part a equation.
Answer:
The data are at the
<u>Nominal</u> level of measurement.
The given calculation is wrong because average (mean) cannot be calculated for nominal level of measurement.
Step-by-step explanation:
The objective here is to Identify the level of measurement of the data, and explain what is wrong with the given calculation.
a)
The data are at the <u> Nominal </u> level of measurement due to the fact that it portrays the qualitative levels of naming and representing different hierarchies from 100 basketball, 200 basketball, 300 football, 400 anything else
b) We are being informed that, the average (mean) is calculated for 597 respondents and the result is 256.1.
The given calculation is wrong because average (mean) cannot be calculated for nominal level of measurement. At nominal level this type of data set do not measure at all , it is not significant to compute their average (mean).
