Answer:
All make numbers make that statement true
Step-by-step explanation:
6406358 + 8550780= 14957138
14957138-5598256= 9358882
therefore is you add any number to 5598256 that is greater than 9358882 then the statement will be true. All those numbers given are larger than 9358882
Answer:
12x^3 - 11x^2 + 9x + 18
Step-by-step explanation:
12x^3 - 20x^2 + 24x + 9x^2 -15x + 18
Combine like terms
12x^3 - 11x^2 + 9x + 18
Answer:
look it up its the same as the equation
Step-by-step explanation:
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.