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11Alexandr11 [23.1K]
3 years ago
11

The 1985 Mexico City earthquake measured a magnitude 8.0 on the Richter scale. The Richter scale uses the function M (I) = log (

StartFraction I Over I Subscript 0 Baseline EndFraction). Which equation relates the intensity of the 1985 earthquake, I, with the intensity of the threshold quake, Io?
A.) I = 810(Io)

B.) Io = 810(I)

C.) I = 108(Io)

D.) Io = 108(I)
Mathematics
1 answer:
Travka [436]3 years ago
7 0

Answer:

The correct option is C: I = 10⁸I₀.   

Step-by-step explanation:

The function of the Richter scale is:

M_{(I)} = log(\frac{I}{I_{0}})

Since the magnitude of the earthquake is 8.0, the relation between the intensity, I, with the intensity of the threshold quake, Io, is:

8.0 = log(\frac{I}{I_{0}})

10^{8} = \frac{I}{I_{0}}

I = 10^{8}I_{0}

Therefore, the correct option is C: I = 10⁸I₀.                

I hope it helps you!                    

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2.191919... as a fraction
larisa [96]

Answer:

See Bottom!

Step-by-step explanation:

This may seem bad, but the answer should be 2191919/1000000

If you require more assistance, please let me know at the bottom.

3 0
3 years ago
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On the number line below. P number what is the value of the opposite of that number.​
Katena32 [7]

Answer: -1 2/4 is the opposite of 1 2/4

Step-by-step explanation: On the number line the P represents 1 2/4, so the opposite of that is -1 2/4.

Also as I stated before I recently did this test.

FLVS right, segment practice test?

Hope this helped fellow FLVS student!!

4 0
3 years ago
A warehouse employs 22 workers on first shift and 14 workers on second shift. Eight workers are chosen at random to be interview
lara [203]
36 all together.
22 first
14 second
8 random chosen

A) all first shift:
One is pulled 22/36
Second is pulled 21/35
Third is pulled 20/34
Fourth 19/33
Fifth 18/32
Sixth 17/31
Seventh 16/30
Eighth 15/29

Multiply all those together
Probability of all first shift is 0.010567296996663
(That means it's not happening anytime soon lol)

B) one worker 14/36
Second 13/35
Third 12/34
Fourth 11/33
Fifth 10/32
Sixth 9/31
Seventh 8/30
Eighth 7/29

Multiply all those together
Probability of all second shift is 0.000099238805645
(That means it's likely to see 100x more picks of all first shift workers before you see this once.. lol)

C) 22/36
21/35
20/34
19/33
18/32
17/31

Multiply..
Probability.. 0.038306451612903


D) 14/36
13/35
12/34
11/33

X... p=0.016993464052288


Probably not correct, haven't done probability in years.
8 0
2 years ago
Use the discriminant to describe the roots of each equation. Then select the best description. 2m2 + 3 = m double root real and
Jlenok [28]

Answer:

The roots of the equation 2m²+3=m are non-real roots.

Step-by-step explanation:

Given equation:

2m²+3=m

2m²-m+3=0

Here, from the equation we can obtain the following values:

a = 2, b = -1, c = 3

Discriminant of an equation is given as:

D = b²-4ac

= (-1)²-4(2)(3)

= 1 - 21

= -20

Discriminant can tell what kinds of roots the equation have.

In our case, the discriminant is less than 0.

When D < 0, the roots of the equation are complex conjugates.(non-real)

8 0
3 years ago
Read 2 more answers
Assignment The operation teeter is defined on the set T= { 2, 3, 5, 7 } by x teeter y=[x+y+xy) mod.8 a - Construct mod.8 table f
rosijanka [135]

Answer:

Case A) tau_net = -243.36 N m, case B)    tau_net = 783.36 N / m,      tau_net = -63.36 N m,  case C)  tau _net = - 963.36 N m,

Explanation:

For this exercise we use Newton's relation for rotation

        Σ τ  = I α

In this exercise the mass of the child is m = 28.8, assuming x = 1.5 m, the force applied by the man is F = 180N

we will assume that the counterclockwise turns are positive.

case a

        tau_net = m g x - F x2

         tau_nett = -28.8 9.8 1.5 + 180 1

        tau_net = -243.36 N m

in this case the man's force is downward and the system rotates clockwise

case b

2 force clockwise, the direction of

the force is up

         tau_nett = -28.8 9.8 1.5 - 180 2

         tau_net = 783.36 N / m

in case the force is applied upwards

3) counterclockwise

       tau_nett = -28.8 9.8 1.5 + 180 2

        tau_net = -63.36 N m

system rotates clockwise

case c

2 schedule

tau_nett = -28.8 9.8 1.5 - 180 3

tau _net = - 963.36 N m

3 counterclockwise

      tau_nett = -28.8 9.8 1.5 + 180 3

      tau_net = 116.64 Nm

the sitam rotated counterclockwise

<h3><u><em>Cr: moya1316</em></u></h3>
4 0
1 year ago
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