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timama [110]
3 years ago
11

2 Select THREE expressions that are equivalent to 16x - 68 A. -4(4x - 17) B-28x + 3) c. 21-8-34) D 4 - 4 - 17) E 8 - 2x-8)

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

Step-by-step explanation:

let's try a:

-4*4x-4*(-17) - expand the distributing terms

-16x-4*(-17) - simplify

-16x-(-68) - simplify again

-16x+68 - remove parentheses

-16x+68 does not equal to 16x-68

lets try b:

-28x+3... dont know what u mean

lets try c:

13-34 first

-21

lets try d:

0-17

-17

lets try e:

-2x+(8-8)

-2x

fortunally dont know what you mean.

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let's set up an equation

4x=24

solve normally:

x=6

so the expression is 4x=24 and she can have 6 kids in each group

6 0
3 years ago
The sum of twice n and 5
yKpoI14uk [10]

Answer:

it is either 2^n+5 or n²+5

Step-by-step explanation:

I'm not one hundred percent sure

4 0
3 years ago
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Three times a certain number, n, is 21​
Phantasy [73]

Answer: 7

Step-by-step explanation:

3n=21

n=7

7 0
3 years ago
7(x-2) - 3x + 5 = -2 (5x-4) + 4<br> Please help asap! - xxx
Oxana [17]

Answer:

x=

2

3

​

=1.500

Step-by-step explanation:

(((7•(x-2))-3x)+5)-((0-2•(5x-4))+4)  = 0

STEP

2

:

Equation at the end of step 2

 ((7 • (x - 2) -  3x) +  5) -  (12 - 10x)  = 0

STEP

3

:

STEP

4

:

Pulling out like terms

4.1     Pull out like factors :

  14x - 21  =   7 • (2x - 3)

Equation at the end of step

4

:

 7 • (2x - 3)  = 0

STEP

5

:

Equations which are never true

5.1      Solve :    7   =  0

This equation has no solution.

A  non-zero constant never equals zero.

Solving a Single Variable Equation:

5.2      Solve  :    2x-3 = 0

Add  3  to both sides of the equation :

                     2x = 3

Divide both sides of the equation by 2:

                    x = 3/2 = 1.500

One solution was found :

x = 3/2 = 1.500

5 0
3 years ago
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Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
wolverine [178]

Answer:

x^4 - 14x^2 - 40x - 75.

Step-by-step explanation:

As complex roots exist in conjugate pairs the other zero is -1 - 2i.

So in factor form we have the polynomial function:

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= (x - 5)(x + 3)( x + 1 - 2i)(x +1 + 2i)

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=  x^2 + 2x + 1 + 4

= x^2 + 2x + 5.

So in standard form we have:

(x^2 - 2x - 15 )(x^2 + 2x + 5)

= x^4  + 2x^3 + 5x^2 - 2x^3 - 4x^2 - 10x - 15x^2 - 30x - 75

= x^4 - 14x^2 - 40x - 75.

7 0
3 years ago
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