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NemiM [27]
3 years ago
13

The length of a rectangular field is represented by the expression14x-3x^2+2y. The width of the field is represented by the expr

ession 5x-7x^2+7y. How much greater is the length of the field than the width?
A) 9x+4x^2-5y
B)9x-10x^2-5y
C)19x+4x^2+9y
D) 19x-10x^2+9y
Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
4 0
The length of the rectangular field is 14x-3x^2+2y, and the width is 5x-7x^2+7y.

To find <span>how much greater is the length of the field than the width we need to subtract the width from the length, so we have:

</span>(14x-3x^2+2y)-(5x-7x^2+7y)=(14x-3x^2+2y)-5x+7x^2-7y.<span>

Operating with the equal degree and variable terms, this difference is equal to

</span>(14x-5x)+(7x^2-3x^2)+(2y-7y)=9x+4x^2-5y
<span>

Answer: A

</span>
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Step-by-step explanation:

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V = L × W × H

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This simplifies to:

x² + x² + 40x + 400 = 10000
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750x+520y=total cost

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