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NemiM [27]
4 years ago
13

The length of a rectangular field is represented by the expression14x-3x^2+2y. The width of the field is represented by the expr

ession 5x-7x^2+7y. How much greater is the length of the field than the width?
A) 9x+4x^2-5y
B)9x-10x^2-5y
C)19x+4x^2+9y
D) 19x-10x^2+9y
Mathematics
1 answer:
Alekssandra [29.7K]4 years ago
4 0
The length of the rectangular field is 14x-3x^2+2y, and the width is 5x-7x^2+7y.

To find <span>how much greater is the length of the field than the width we need to subtract the width from the length, so we have:

</span>(14x-3x^2+2y)-(5x-7x^2+7y)=(14x-3x^2+2y)-5x+7x^2-7y.<span>

Operating with the equal degree and variable terms, this difference is equal to

</span>(14x-5x)+(7x^2-3x^2)+(2y-7y)=9x+4x^2-5y
<span>

Answer: A

</span>
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Find the volume and surface area of the square pyramid
Montano1993 [528]

The volume and surface area of the pyramid will be 392 / 3 cubic units and 189 square units. Then the correct option is A.

The complete question is attached below.

<h3>What is the volume and surface area of the pyramid? </h3>

Suppose the base of the pyramid has length = L units, width = W units, slant height = K units, and the height of the pyramid is of H units.

Then the volume of the pyramid will be

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The surface area of the pyramid will be

SA = 2(1/2 × B × K) + 2(1/2 × L × K) + (L × B)

Then the volume will be

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V = 392/3 cubic units

Then the surface area will be

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SA = 189 square units

Then the correct option is A.

More about the volume and surface area of the pyramid link is given below.

brainly.com/question/23302816

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2 years ago
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