Answer:
Age Frequency Cumulative Frequency
Less than 30 27 27
Less than 40 37 27 + 37 = 64
Less than 50 1 1 64 + 11 = 75
Less than 60 3 75 + 2 = 77
Less than 70 5 77 + 5 = 82
Less than 80 1 82 + 1 = 83
Less than 90 2 83 +2 = 85
Step-by-step explanation:
Given:
The Frequency Distribution table of ages of best actresses when award was won
To find:
Construct the cumulative frequency distribution
Solution:
In order to construct cumulative frequency distribution for the given data, each frequency from above table is added to the sum of the previous frequencies. For example, frequency for Less than 40 is 37 and the previous frequency (less than 30) is 27 so in order to calculate cumulative frequency 27 i.e. previous frequency is added to 37 (frequency of less than 30). The complete table is given above.
Answer:
m∠X = 29°
m∠V = 61°
m∠W == 90°⇒given
Step-by-step explanation:
∵ ΔXWV is right angle at W
∴ m∠W = 90°
∴ m∠X + m∠V = 180° - 90° = 90°
∵ m∠X = 2x + 5 and m∠V = 4x +13
∴ 2x + 5 +4x + 13 = 90
∴ 6x + 18 = 90
∴ 6x = 90 - 18 =72
∴ x = 72/6 = 12
∴ m∠X = 2(12) + 5 = 29°
∴ m∠V = 4(12) + 13 = 61°
P + s = 200......p = 200 - s
20p + 15s = 3400
20(200 - s) + 15s = 3400
4000 - 20s + 15s = 3400
-20s + 15s = 3400 - 4000
-5s = - 600
s = -600/-5
s = 120 <=== there were 120 standard tickets sold
p + s = 200
p + 120 = 200
p = 200 - 120
p = 80 <=== there were 80 premium tickets sold
Answer:
11 am
Step-by-step explanation:
Bus A and Bus B leave the bus depot at 9 am.
Bus A takes 30 minutes to complete its route once
Bus B takes 40 minutes to complete its route once.
We solve this finding the Lowest Common Multiple of the minutes each bus uses to complete it's route
30 = 3 × 10
40 = 4 × 10
= 3 × 4 × 10
= 120 minutes
120 minutes after 9 am is
60 minutes = 1 hour
60 minutes = 1 hour
= 2 hours.
9am + 2 hours
= 11 am.
Therefore, they be back at the bus depot together at 11 am
