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sergeinik [125]
3 years ago
15

A number, f is positive

Mathematics
2 answers:
monitta3 years ago
6 0

Answer:

Not enough information.

Step-by-step explanation:

Masteriza [31]3 years ago
4 0
What are you asking?
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Help please!!!!!<br> Geometry
RideAnS [48]

Answer:

E.

Step-by-step explanation:

E gets prio rather than D & F, so E is the first letter. after that, D has more prio than F. so the answer is EDF.

5 0
3 years ago
At a particular garage, 60% of the customers require an oil change, 20% require tire rotation, and 75% of customers require at l
ZanzabumX [31]

Answer:

a. 5%

b. 55%

c. 70%

Step-by-step explanation:

a. The probability of customer wanting both services (P(O&T)) is:

P(O)+P(T)+P(O\&T) = 0.75\\P(O)+P(O\&T) =0.60\\P(T)+P(O\&T) = 0.20\\P(O)+P(T)+P(O\&T) -[P(O)+P(T)+2P(O\&T)]=0.75 -(0.60-0.20)\\P(O\&T)=0.05=5\%

The probability is 5%

b. The probability that the customer will need an oil change, but not a tire rotation (P(O)) is :

P(O)+P(O\&T) = 0.60\\P(O\&T) = 0.05\\P(O) =0.60-0.05 = 0.55 = 55\%

The probability is 55%

c. The probability that the customer will want exactly one of these two services (P(O)+P(T)) is:

P(O)+P(T)+P(O\&T) = 0.75\\P(O\&T) = 0.05\\P(O)+P(T) =0.75-0.05 = 0.70 = 70\%

The probability is 70%

4 0
3 years ago
Read 2 more answers
Pls Answer
atroni [7]

Answer:

#1

7(y+3)=5y+8

7y+21=5y+8

7y-5y=8-21

2y=-13

2y/2=-13/2

y=-6.5

7 0
3 years ago
Please help, need asap
rodikova [14]
For the first option, since when x is going down (to the left) the function is going up, it's not approaching 0. For the second option, since when x is going up (to the right) it's going up, it's not approaching negative infinity (negative infinity is all the way down). For the third one, since when x is going down the y values are climbing, we can assume that the function's values go to positive infinity. For the last one, since when x=0 y=0, when x=0 the function does not go to infinity
8 0
4 years ago
Activity 1.1 Simplify Me Simplify by removing perfect nth powers: 1. √20 2. √300 3. √128 3 4. √ 5 3 5. √50 3
LekaFEV [45]

Answer:

(a)\ \sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128} = 8 \sqrt{2}

Step-by-step explanation:

Required

Simplify

(a)\ \sqrt{20}

Express 20 as 4 * 5

\sqrt{20}=\sqrt{4 * 5}

Split

\sqrt{20}=\sqrt{4} * \sqrt{5}

This gives:

\sqrt{20}=2 * \sqrt{5}

\sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300

Express as 100 * 3

\sqrt{300} = \sqrt{100} * \sqrt{3}

This gives:

\sqrt{300} = 10 * \sqrt{3}

\sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128}

Express as 64 * 2

\sqrt{128} = \sqrt{64*2}

Split

\sqrt{128} = \sqrt{64} * \sqrt{2}

\sqrt{128} = 8 * \sqrt{2}

\sqrt{128} = 8 \sqrt{2}

<em></em>

<em>Questions 4 and 5 are not clear</em>

<em>Follow the steps in 1 - 3 to solve 4 and 5</em>

7 0
3 years ago
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