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tiny-mole [99]
3 years ago
10

Edward’s recipe for salad uses a ratio of 3 3/4 cups of lettuce to 1/2 lb of tomatoes. Use a complex fraction to compare the amo

unt of lettuce to the amount of tomatoes. Determine how many cups of lettuce Edward needs to mix with 1 lb of tomatoes. Show your work.
Mathematics
1 answer:
adelina 88 [10]3 years ago
4 0

Answer:

a)  \frac{2 \frac{1}{4}}{ \frac{1}{2}}  

b) \frac{1}{2} • 2 = 1

so  \frac{9}{4} • 2 =  \frac{9}{2} cups (which is 4 \frac{1}{2}  )

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A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu
telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 110, p = 0.2

So

\mu = E(X) = np = 110*0.2 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4.1952}

Z = 0.715

Z = 0.715 has a pvalue of 0.7626.

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 22}{4.1952}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

4 0
3 years ago
What is the sign of the product (–5)(–3)(–8)(–6)? Positive, because the products (–5)(–3) and (–8)(–6) are negative, and the pro
chubhunter [2.5K]

Answer:

The product (–5)(–3)(–8)(–6) should be Positive.

Step-by-step explanation:

The product of 2 negative numbers equal a positive product.

N * N = P

-5*-3=15

-8*-6=48

The product of 2 positive numbers is positive.

P * P = P

15 * 48 = 720

Your answer should be: Positive because the products (–5)(–3) and (–8)(–6) are positive, and the product of two positive numbers is positive.

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Answer:

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Step-by-step explanation:

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