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rusak2 [61]
2 years ago
10

PLEASE HELP see picture 66 pts LOGARITHMIC

Mathematics
1 answer:
Nostrana [21]2 years ago
4 0
Ln(x) should be the answer
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Sean was at baseball batting practice. He swung 25 times and only hit the ball 15 times. So, how many times did he miss?
Lorico [155]

Answer: 10

Step-by-step explanation:

If Sean swung 25 times, and only hit the ball 15 times, he missed 10 times. 25-15=10

4 0
3 years ago
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Which is equivalent to 4/9 divided by 5/7
jarptica [38.1K]
28/45 or as a decimal 0.62
4 0
3 years ago
Megan and Suzanne each have a plant. They track the growth of their plants for four weeks.
Alenkinab [10]

Answer: Megan's at 3 inches per week

3 0
2 years ago
Suppose a basketball player is practicing shooting, and has a prob-ability .95 of making each of his shots. Also assume that his
Karo-lina-s [1.5K]

Answer:

0.082

Step-by-step explanation:

Number of attempts = n = 100

Since there are only two outcomes and in-dependent of each other, the probability of missing a shot  = 1 - Probability of making each shot

p = 1 - 0.95 = 0.05

Possion Ratio (λ) = np where n is the number of events and p is the probability of the shot missing

λ = 100 x 0.05 = 5

Define X such that X = Number of misses and X ≅ Poisson (λ = 5)

P [X ≤ 2] = P [X = 0] + P [X = 1] + P [X = 2]

P [X ≤ 2] = e⁻⁵ + e⁻⁵ x 5 + e⁻⁵ x 5²/2!

P [X ≤ 2] = e⁻⁵ [1 + 5 + 5²/2!]

P [X ≤ 2] = e⁻⁵ x 12.25 = 0.082

The required probability that there are at most 2 misses in the first 100 attempts is 0.082

7 0
3 years ago
If y=x^2+kx-k for what values of k will the quadratic have 2 real solutions
xeze [42]

The key to answering this question lies in finding the discriminant b^2-4ac. If b^2-4ac is greater than zero, the quadratic equation will have 2 real solutions.

Typing out y=x^2+kx-k, we see that a=1, b=k and c = -k. The discriminant in this case is

b^2 - 4(a)(c), or k^2 - 4(1)(-k), or k^2 + 4k

For which k is this k^2 + 4k = 0? Factor k^2 + 4k, obtaining k(k+4) = 0; the roots of this are k=0 and k = -4.

Now set up a number line for k, drawing empty circles at k = 0 and k = -4. These two values divide the number line into three intervals:

(-infinity, -4), (-4, 0) and (0, infinity). Choose a test number for each interval:

-6 for the first, -2 for the second and 4 for the third. Determine whether k^2 + 4k > 0 for any of these test numbers:

(-6)^2 + 4(-6) = 36 - 24 = +12. Yes, the discriminant is + on the interval (-infinity, -4)

(-2)^2 + 4(-2) = 4 - 8 = -4. No, the discriminant is not + on (-4, 0).

(4)^2 + 4(4) = 32. Yes, the discrim. is + on (0, infinity).

So: The given quadratic will have two different, real roots on the two intervals (-infinity, -4) and (0, infinity).

4 0
3 years ago
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