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Evgen [1.6K]
3 years ago
5

Please if ur good at pre calc stop to help with the first question please

Mathematics
1 answer:
vova2212 [387]3 years ago
5 0

Answer:

Step-by-step explanation:

The first thing you ought to do is find out what you are trying to get. Desmos is an ideal program to do that if you don't have a graphing calculator. Just search for Desmos. It is pretty obvious once you get there.  I've enclosed the graph to show you what it looks like.

Notice what happens around 5.  The graph splits because effectively, you are dividing by 0 when you put 5 into the denominator. The question arises why doesn't the same thing happen at 0. It should: There is a discontinuity but it is very tiny. So the domain numbers that you should graph are

-1   0™  1   2   3   4   4.5    4.8   5.3    5.4  6 7

™I wouldn't make 0 a part of this domain.  But you can indicate with a dot where the graph goes.

I haven't filled in the range numbers. That's your job. All you have to do is fill in the table with points. Or you can put them on the graph that I have enclosed just to see where they points belong.

A graph is not to convey accuracy. It is to show the shape of function in question.

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How do you solve this?
puteri [66]

Answer:

Width: 7

Length: 14

Step-by-step explanation:

The area of a rectangle can be found my multiplying the length by the width. We do not know neither the length nor the width. However, we do know that the length is 7 feet longer than the width. Because we do not know the value of either side, let's let x represent the width.

Since the length is 7 feet longer, we can represent the length by x+7.

Now that we have our values for the length and the width we can multiply them together to find our area.

(x)(x+7)=x^{2} +7x

Now we have our equation, so we can address the changes made by the original question. The original question states that when 7 is added to both the length and width the area becomes 3 times larger. To do so simply increase each side by 7 by adding 7 to the original values.

(x+7)(x+14)

And multiply our area by 3.

3(x^{2} +7x)

set these equal to each other to find your new equation.

(x+7)(x+14)=3(x^{2} +7x)

Now you need to solve for x. To do this first muliply (x+7) and (x+14).

(x+7)(x+14)=\\x^{2} +14x+7x+98=\\x^{2} +21x+98

Then multiply 3(x^{2} +7x)

3(x^{2} +7x)=\\3x^{2} +21x

Now you can begin solving for x.

x^{2} +21x+98=3x^{2} +21x

Subtract x^{2} from both sides.

21x+98=2x^{2} +21x

Subtract 21x from both sides.

98=2x^{2}

Divide by 2.

49=x^{2}

And finally take the sqaure root of both sides.

\sqrt{x^{2} }=\sqrt{49}\\x=7

Remember, because we are dealing with length, there cannot be negative. So while normally we would get both +7 <em>and</em> -7, in this case we <em>only </em>get +7.

Now that we have the value of x, we can plug it into our original values.

For width we simply get 7.

For length we get 7+7=14

To check our answer we cna multiply 7 by 14 to get 98. Then we can add 7 to our length and width to get 14 and 21. Multiply these together and we get 294. 294 divided by 3 is 98, proving our answer correct.

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