Answer:
a) there is s such that <u>r>s</u> and s is <u>positive</u>
b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r
Step-by-step explanation:
a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.
b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.
Ok, so;
Let me draw the figure here below:
We know that the area of a circle can be found using the next equation:
Area = πr².
Where r is the radius and π is a number.
So, the area of this circle, will be:
Area = π(1km)²
Area = π km²
For solving this question we will use the relationship between the range of data and the spread of data. The relationship is that "Higher the Range of the Data, Higher is the Spread and lower the range of the data then lower is the spread".
So, keeping in mind this definition let us proceed and check each option and measure their range.
We know that Range is measured as
Range=(Highest Value of the Data)-(Lowest Value of the Data)
a. 13.7-3.1=10.6
b. 423.6-1.3=422.3
c. 38.4-7.2=31.2
d. 231.4-5.5=225.9
As we can see Option b. has the largest range and as range is a measure of spread then option b is the distribution which has the largest spread.
Answer:
270 minutes per boy.
Step-by-step explanation:
45 mins each week
multiplies by 6