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DedPeter [7]
3 years ago
15

What is the product? (-2d^2+s)(5d^2-6s)

Mathematics
2 answers:
Ulleksa [173]3 years ago
7 0
(-2d^2+s)(5d^2-6s)
= (-2d^2*5d^2 + s*5d^2 -2d^2*-6s + s*-6s
= -10d^4 + 5sd^2 + 12sd^2 - 6s^2
=-10d^2 + 17sd^2 - 6s^2
This is the final result
densk [106]3 years ago
4 0

Answer:

It's B on edge.

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Help Please I did to finsh
ki77a [65]

Step-by-step explanation:

Hello there!

Again, plug this into the Pythagorean Theorem.

a^2+b^2=c^2\\2^2+b^2=6^2\\4+b^2=36\\b^2=32\\b=5.65

:)

7 0
3 years ago
Read 2 more answers
A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company prod
tekilochka [14]

Answer:

C) 515 hours.

D) 500 hours

c) sample 3

Step-by-step explanation:

1. Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample Service Life (hours)

1                2              3

495      525            470

500         515           480

505        505            460

<u>500         515             470        </u>

<u>∑2000     2060         1880</u>

x1`= ∑x1/n1= 2000/4= 500 hours

x2`= ∑x2/n2= 2060/4= 515 hours

x3`= ∑x3/n3= 1880/4=  470 hours

2. The mean of the sampling distribution of sample means for whenever service life is in control is 500 hours . It is the given mean in the question and the limits are determined by using  μ ± σ , μ±2 σ  or μ ± 3 σ.

In this question the limits are determined by using  μ ± σ .

3. Upper control limit = UCL = 520 hours

Lower Control Limit= LCL = 480 Hours

Sample 1 mean = x1`= ∑x1/n1= 2000/4= 500 hours

Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample 3 mean = x3`= ∑x3/n3= 1880/4=  470 hours

This means that the sample mean must lie within the range 480-520 hours but sample 3 has a mean of 470 which is out of the given limit.

We see that the sample 3 mean is lower than the LCL. The other  two means are within the given UCL and LCL.

This can be shown by the diagram.

8 0
2 years ago
When finding the volume of a rectangle shaped 3D box, what formula do you use?
stiv31 [10]

Answer:

length x width x height

l x w x h

8 0
2 years ago
p varies directly as q and inversely as r. One set of values is p = 5, q = 1, and r = 2. Find p when q = 10 and r = 50.
kari74 [83]
P = kq/r

5 = k*1/2
k = 2*5 = 10

p = 5*10/50 = 1
P is 1.

Hope it helps!
6 0
3 years ago
For what values of a is the value of the binomial 2a-1 smaller than the value of the binomial 7-1.2a
Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

2a-1<7-1.2 a

2a+1.2a<7+1

3.2 a<8

a<(8/3.2)

or a<(80/32)

or a<5/2

or a<2.5

3 0
3 years ago
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