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3 years ago

What is the product? (-2d^2+s)(5d^2-6s)

2 answers:

7 0

(-2d^2+s)(5d^2-6s)
= (-2d^2*5d^2 + s*5d^2 -2d^2*-6s + s*-6s
= -10d^4 + 5sd^2 + 12sd^2 - 6s^2
=-10d^2 + 17sd^2 - 6s^2
This is the final result

densk [106]3 years ago

4 0

Answer:

It's B on edge.

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Solve for x. round to the nearest hundredth if necessary.

iris [78.8K]

Answer: $x=11.47$

Step-by-step explanation:

Given the angle of 55 degrees, you know that the adjacent side is "x" and the length of the hypotenuse is 20.

Therefore, you need to remember the following identity:

$cos\alpha=\frac{adjacent}{hypotenuse}$

Then, knowing that:

$\alpha=55\°\\adjacent=x\\hypotenuse=20$

You need to substitute these values into $cos\alpha=\frac{adjacent}{hypotenuse}$ :

$cos(55\°)=\frac{x}{20}$

Now, you can solve for "x":

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2 years ago

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Allisa [31]

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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1 year ago

Evaluate |2y-2| when y=-2

grandymaker [24]

Answer:

Step-by-step explanation:

|2y-2| when y = 2

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2 years ago

What is the midpoint and distance between points P(3,5) and Q(7,5)

storchak [24]

The formula of a midpoint:

$M\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points P(3, 5) and Q(7, 5). Substitute:

$x=\dfrac{3+7}{2}=\dfrac{10}{2}=5\\\\y=\dfrac{5+5}{2}=\dfrac{10}{2}=5$

$d=\sqrt{(5-5)^2+(7-3)^2}=\sqrt{0^2+4^2}=\sqrt{4^2}=4$

<h3>Answer:</h3><h3>Midpoint = (5, 5)</h3><h3>Distance = 4</h3>

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3 years ago