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4 years ago

What are the possible numbers greater than 42 that would have the same GCF as the numbers 24 and 48?

Mathematics

1 answer:

GrogVix [38]4 years ago

3 0

Bdhdhdhdhdhdhhdjdjdhdhjshdbdjjdduhd

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I really don't get his

Angelina_Jolie [31]

Answer:

40.32 sqcm

Step-by-step explanation:

For two similar polygons, ratio of corresponding sides are equal.

Here, ratio of breadth = 4.8/4 = 1.2

So, length of the larger rectangle = 7 * 1.2 = 8.4

So, area of the larger triangle = 4.8 * 8.4 sqcm = 40.32 sqcm

6 0

3 years ago

2ax-b=cx+d solve for x

Alexxandr [17]

Answer:

x = (d + b) / (2a - c)

Step-by-step explanation:

2ax-b = cx+d

2ax - cx = d + b

x (2a-c) = d + b

x = (d + b) / (2a - c)

7 0

3 years ago

A class contains 8 boys and 14 girls. Two of the students are to be selected as student council representatives. What is the pro

erastova [34]

The answer is 3/10 but that’s not one of your options

4 0

3 years ago

What is one half divided by two thirds

Ber [7]

See the attachment in the file below

6 0

3 years ago

Read 2 more answers

How do I solve this?<br><br> -6x-1+5x^2 = 8x^2<br><br> Thanks

max2010maxim [7]

Answer:

$\displaystyle x=\frac{-3+\sqrt{6}}{3}\text{ and } x=\frac{-3-\sqrt{6}}{3}$

Or, by approximating:

$x\approx-0.1835\text{ or } x\approx -1.8165$

Step-by-step explanation:

Let’s convert this to standard form. We have:

$-6x-1+5x^2=8x^2$

Subtract 5x² from both sides:

$-6x-1=3x^2$

And add 6x and 1 to both sides:

$0=3x^2+6x+1$

This is not factorable. So, we will need to use the quadratic formula.

The quadratic formula for a quadratic in standard form is given by:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}}$

In this case, a=3; b=6, and c=1.

Substitute appropriately:

$\displaystyle x=\frac{-6\pm\sqrt{6^2-4(3)(1)}}{2(3)}$

Simplify:

$\displaystyle x=\frac{-6\pm\sqrt{24}}{6}$

We can simplify the square root:

$\sqrt{24}=\sqrt{4}\cdot\sqrt{6}=2\sqrt{6}$

Hence:

$\displaystyle x=\frac{-6\pm2\sqrt{4}}{6}$

Simplify:

$\displaystyle x=\frac{-3\pm\sqrt{6}}{3}$

Hence, we will have two solutions:

$\displaystyle x=\frac{-3+\sqrt{6}}{3}\text{ and } x=\frac{-3-\sqrt{6}}{3}$

Approximating them, we can see that our solutions are approximately:

$x\approx-0.1835\text{ or } x\approx -1.8165$

7 0

3 years ago