Answer:
We can use a trick here. Let's look at the first few exponents of i to realize this:
i^0 = 1
i^1 = i
i^2= -1
i^3 = -i
i^4 = 1
i^5 = i
i^6 = -1
i^7 = -i
we can see that the pattern (1, i, -1, -i) repeats. Since 82/2 = 41, and 41 is only divisible by 1, i^41 = i, and i^2 = -1. -1*i = -i, so i^82 = -i.
Step-by-step explanation:
Answer:
The anwerss to the question are
(A) P(No less than two people use their phones while driving) = 0.1225
(B) P(The probability that no more than one person of the three people use their cell phone while driving) = 0.147875
Step-by-step explanation:
The given relations are
Percentage of motorists that routinely drive while sing their phone = 35 %
The probaboloty that if a peerson is random;ty selected from a group of hudred person routinely uses their phone wjile friving P(phone) = 35
The probability that a motorist randomly selected fron a set of 100 do not routinely use thir phones while driving = P(No celll phone) = 65
Then the probability that when three people are selected at random at least two people of the three people use their cell phone while driving is
P(phone) = 35/100m = 0.35
P(No celll phone) = 65/100 = 0.65
(A) Probability of at least two of three use their phones whle driving is
0.35×0.35×0.65 +0.35×0.35×0.35 = 0.1225
(B) The probability of only one person out of three seted use their phones while driving is
(0.35)(0.65)(0.65) = 0.147875
Answer:
-5
Step-by-step explanation:
Hope this helps
9(30+7) = (9*30)+(9*7)
This is the distributive property
x(y+z) = xy + xz
Let the dash = x
9(30+7) = (9*x)+(9*7)
9(37) = 9x + 63
333 = 9x + 63
Substract 63 from both sides
333 - 63 = 9x +63-63
270 = 9x
Divide both sides by 9
270/9 = 9x/9
30 = x
Or x = 30