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Flura [38]
3 years ago
10

What is this expression in simplified form? (v22)(5v2)​

Mathematics
1 answer:
elixir [45]3 years ago
3 0

Answer:

5v24

Step-by-step explanation:

(v22)(5v2) = 5v(2+22) = 5v24

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que que

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Write the trig ratios based on E
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8 0
3 years ago
On February 1, the electricity meter reading for the Smith residence was 19,423 kilowatt hours. On March 1, the meter read 20,28
Karolina [17]
A. How many kilowatt hours of electricity did the Smiths use during February?

Kilowatt hours of electricity the Smiths used during February:
Meter read on March 1 - meter read on February 1 =
20,288 kilowatt hours - 19,423 kilowatt hours =
865 kilowatt hours
Answer: The Smiths used 865 kilowatt hours of electricity during February

b. How many kilowatt hours did they use during March?

Kilowatt hours of electricity the Smiths used during March:
Meter read on April 1 - meter read on March 1 =
21,163 kilowatt hours - 20,288 kilowatt hours =
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Answer: The Smiths used 875 kilowatt hours of electricity during March
8 0
4 years ago
Which graph shows the function y = ( 1/3)3x?​
arlik [135]

Answer:

the first one

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y = 3x/3

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7 0
3 years ago
Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?​
Nutka1998 [239]

Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}

  • {\dashrightarrow \sf{Principle = Rs.30000}}
  • {\dashrightarrow \sf {Time = 4 \: years}}
  • \dashrightarrow \sf{Rate = 30\%}
  • \begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}

  • \dashrightarrow{\sf{Simple \: Interest }}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}

\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}

Where

  • \dashrightarrow{\sf{S.I = Simple \:  Interest }}
  • {\dashrightarrow{\sf{P = Principle }}}
  • {\dashrightarrow{\sf{ R = Rate }}}
  • {\dashrightarrow{\sf{T = Time}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{P \times R \times T}{100}}}}}}

Substituting the values

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 120}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{3600000}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\cancel{\dfrac{3600000}{100}}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{Rs.36000}}}}}

{\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}

  • Henceforth,The Simple Interest is Rs.36000..

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

8 0
3 years ago
Read 2 more answers
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