Answer:
Rounding to nearest hundredths gives us r=0.06.
So r is about 6%.
Step-by-step explanation:
So we are given:
where
.
Divide both sides by 1600:
Simplify:
Take the 6th root of both sides:
![\sqrt[6]{\frac{23}{16}}=1+r](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B%5Cfrac%7B23%7D%7B16%7D%7D%3D1%2Br)
Subtract 1 on both sides:
![\sqrt[6]{\frac{23}{16}}-1=r](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B%5Cfrac%7B23%7D%7B16%7D%7D-1%3Dr)
So the exact solution is ![r=\sqrt[6]{\frac{23}{16}}-1](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B6%5D%7B%5Cfrac%7B23%7D%7B16%7D%7D-1)
Most likely we are asked to round to a certain place value.
I'm going to put my value for r into my calculator.
r=0.062350864
Rounding to nearest hundredths gives us r=0.06.
Answer:
x^3-3x=0
+3x
x^3=3x
ok so that means that that number cubed is the same as a number squared so
x = 0
x = -sqrt(3)
x = sqrt(3)
im going say the answer is mostly likely 0 but it could be the other ones
Hope This Helps!!!
Her statement is possible, the first rectangle could be equal to the second because x is unknown so if x was 5in in the first rectangle and - 1 in the second rectangle both problems would look like this 2 in & 5 in and the second one 5in & (2 in = (-1 +3)).
Answer:
16
Step-by-step explanation:
Lets assume x is Elgas' age
And y is Alvins age
we know that alvin is 11 years younger than Elga which means,
x=y+11
and the sum of their age is 43
x+y=43
solve it and you get 16
