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Juliette [100K]

3 years ago

8

150 is 25% of what number? Four students solved this problem using equivalent ratios. Choose the student whose work is correct.

2 answers:

jenyasd209 [6]3 years ago

6 0

Answer:

liam's answer is correct

Step-by-step explanation:

2 years ago

ty

Tema [17]3 years ago

4 0

Answer:

Yes it is Liam

Step-by-step explanation:

Good job other guy! :)

2 years ago

ty

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An article in the Journal of Aircraft described a new equivalent plate analysis method formulation that is capable of modeling a

mezya [45]

Answer:

Given:

n = 15

c = 95% = 0.95

Let us assume:

α = 0.05

Determine the difference in value of each pair.

→See attached for the table←

→See attached for the for the workings←

Result

a) There is sufficient evidence to reject the claim that the two methods provide the same mean value for natural vibration frequency.

b) (-10.9646, -0.0068)

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3 years ago

Help please! (See image.)

Scorpion4ik [409]

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3 years ago

What is 5 1/4 divided by 1 5/9?

Sonbull [250]

21/4 ÷ 14/9
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3 years ago

Read 2 more answers

Which Expression is a factor of 16a2 − 25

kipiarov [429]

Answer:

should be (4a-5)x(4a+5)

Step-by-step explanation:

5 0

2 years ago

One more question on this test guys. please answer as fast as possible. If you do,

GaryK [48]

1. The given rectangular equation is $x=2$ .

We substitute $x=r\cos \theta$ .

$r\cos \theta=2$

Divide through by $\cos \theta$

$r=\frac{2}{\cos \theta}$

$r=2}\sec \theta$

$\boxed{x=2\to r=2\sec \theta}$

2. The given rectangular equation is:

$x^2+y^2=36$

This is the same as:

$x^2+y^2=6^2$

We use the relation $r^2=x^2+y^2$

This implies that:

$r^2=6^2$

$\therefore r=6$

$\boxed{x^2+y^2=36\to r=6}$

3. The given rectangular equation is:

$x^2+y^2=2y$

This is the same as:

We use the relation $r^2=x^2+y^2$ and $y=r\sin \theta$

This implies that:

$r^2=2r\sin \theta$

Divide through by r

$r=2\sin \theta$

$\boxed{x^2+y^2=2y\to r=2\sin \theta}$

4. We have $x=\sqrt{3}y$

We substitute $y=r\sin \theta$ and $x=r\cos \theta$

$r\cos \theta=r\sin \theta\sqrt{3}$

This implies that;

$\tan \theta=\frac{\sqrt{3}}{3}$

$\theta=\frac{\pi}{6}$

$\boxed{x=\sqrt{3}y\to \theta=\frac{\pi}{6}}$

5. We have $x=y$

We substitute $y=r\sin \theta$ and $x=r\cos \theta$

$r\cos \theta=r\sin \theta$

This implies that;

$\tan \theta=1$

$\theta=\frac{\pi}{4}$

$\boxed{x=y\to \theta=\frac{\pi}{4}}$

6 0

3 years ago