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algol [13]
3 years ago
9

What is the domain of the function shown in this graph?

Mathematics
1 answer:
NeX [460]3 years ago
8 0

Domain is the set of x. Therefore, the domain starts from least x-value or from left side to the right side.

In the graph, it shows that the domain is from x = 1 to positive infinity.

Therefore the answer is x >= 1

or [1,+infinity) as interval.

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Expand the following using either the Binomial Theorem or Pascal’s Triangle. You must show your work for credit.
madam [21]
The binomial coefficients are 1,5,10,10,5,1     (5/0, 5/1, 4/2, 3/3, 2/4, 1/5)

x^5-25x^4+250x^3-1250x^2+3125x-3125


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Expanded form for 2,937,082
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Two friends, Alejandra and Mia, agreed to split the check at a restaurant. Alejandra ordered $12 worth of food and Mia ordered $
dedylja [7]
12+18=30 so together they have $30.00 in all.
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<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D
Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
Translate and solve: 82% of what number is 369?
sergeinik [125]

Answer:

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