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2 years ago

Someone please help me I’m desperate

Mathematics

2 answers:

Levart [38]2 years ago

5 0

Answer:

2nd one

Step-by-step explanation:

xxTIMURxx [149]2 years ago

4 0

Answer:

f > 12......................

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What fraction is equal to 3/5? 12/20 16/25 20/30 26/40

Debora [2.8K]

12/20 is equivalent to 3/5.

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2 years ago

In 1940 you could buy a soda for 5 cents. Today the average cost of the same size soda is $1.25. What is the percent of increase

svlad2 [7]

Answer:

2400%

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Pls help me in this i really need help :( :)

Andrews [41]

Hello and Good Morning/Afternoon:

Let's take this problem step-by-step:

First off, let's write the line in point-slope form:

$\rm \hookrightarrow (y-y_0)=m(x-x_0)$

(x₀, y₀) any random point on the line
'm' is the value of the slope

Let's calculate the slope:

$\rm \hookrightarrow Slope = \frac{y_2-y_1}{x_2-x_1}$

(x₁, y₁): any random point on the line ⇒ (-2, -6)
(x₂,y₂): any random point on the line that is not (x₁, y₁) ⇒ (2, -3)

$\rm \hookrightarrow slope = \frac{-3--6}{2--2} =\frac{3}{4}$

Now that we found the slope, let's put it into the point-slope form

⇒ we need (x₀, y₀) ⇒ let's use (2,-3)

$(y-(-3))=\frac{3}{4} (x-2)\\y+3=\frac{3}{4} (x-2)$

The equation, however, could also be put into 'slope-intercept form'

⇒ gotten by isolating the 'y' variable to the left

$y = \frac{3}{4}x-\frac{9}{2}$

Answer: $y = \frac{3}{4}x-\frac{9}{2}$ or $y+3=\frac{3}{4} (x-2)$

*Either equations work, put the one that you are the most familiar with

Hope that helps!

#LearnwithBrainly

5 0

1 year ago

Answer for both of them 3(4x - 1) 2x + 4

kobusy [5.1K]

Answer: 12x-3 and 2x+4

Step-by-step explanation: i don’t know if i wanted to add them together. you j distribute that’s how i got my answer.

5 0

2 years ago

Read 2 more answers

What is the sum of the first 51 consecutive odd positive integers?

Angelina_Jolie [31]

We call:

$a_{n}$ as the set of the first 51 consecutive odd positive integers, so:

 $a_{n} = \{1, 3, 5, 7, 9...\}$

Where:
$a_{1} = 1$
$a_{2} = 3$
$a_{3} = 5$
$a_{4} = 7$
$a_{5} = 9$
and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

 $a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}$

Then:

 $a_{n} = a_{1} + (n-1)d$

So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

 $S_{k} = ( \frac{a_{1} + a_{k}}{2} ).k$

Therefore, we need to find:
 $a_{k} = a_{51}$

Given that $a_{1} = 1$ , then:

$a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1$

Thus:
$a_{k} = a_{51} = 2(51)-1 = 101$

Lastly:

$S_{51} = ( \frac{1 + 101}{2} ).51 = 2601$

4 0

3 years ago