The answer to your question would be A. hope this helps...
The moles of Al that is needed to react with 6.34 moles of Fe3O4 is 16.9 moles
<u><em> Explanation</em></u>
<em> </em>8 Al+ 3Fe3O4 → 4 Al2O3 + 9Fe
use of mole ratio of Al: fe3O4 to calculate the moles of Al
The mole ratio of Fe3O4 : Al is 8:3 therefore the moles of Al =
6.34 moles x8/3 = 16.9 moles
Answer:
n = 6.06 x
mol
Explanation:
n =?
m = 3.06 x 10-³ g
M (H5) = 5 x 1.01 (Since we only want hydrogen)
Atomic mass of C = 12.01
Atomic mass of H is 1,01, etc.
Having this data, we can use the Molar mass formula and change it so we can know the quantity of matter (n) in moles, and we just replace it.
M =
⇔ n =
⇔ n =
⇔ n = 6.06 x
mol
Note: The numbers I've used may be different from yours, by a small difference. I don't know if it's the case, but hope it helped.
The volume of serum that contains 2.g of NaCl is 0.244L
The answer is C 54.055 grams