<h3>Answer:</h3>
NH₃ > NH₄NO₃ > (NH₄)₂HPO₄ > (NH₄)₂SO₄ > KNO₃ > (NH₄)H₂PO₄
<h3>Soution:</h3>
In (NH₄)₂HPO₄:
Mass of Nitrogen = N × 2 = 14 × 2 = 28 g.mol⁻¹
Molar Mass of (NH₄)₂HPO₄ = 132.06 g.mol⁻¹
Mass %age = Mass of N / M.Mass of (NH₄)₂HPO₄ × 100
Mass %age = 28 g.mol⁻¹ / 132.06 g.mol⁻¹ × 100
Mass %age = 21.20 %
In (NH₄)₂SO₄:
Mass of Nitrogen = N × 2 = 14 × 2 = 28 g.mol⁻¹
Molar Mass of (NH₄)₂SO₄ = 132.14 g.mol⁻¹
Mass %age = Mass of N / M.Mass of (NH₄)₂SO₄ × 100
Mass %age = 28 g.mol⁻¹ / 132.14 g.mol⁻¹ × 100
Mass %age = 21.18 %
In KNO₃:
Mass of Nitrogen = N × 1 = 14 × 1 = 14 g.mol⁻¹
Molar Mass of KNO₃ = 101.10 g.mol⁻¹
Mass %age = Mass of N / M.Mass of KNO₃ × 100
Mass %age = 14 g.mol⁻¹ / 101.10 g.mol⁻¹ × 100
Mass %age = 13.84 %
In (NH₄)H₂PO₄:
Mass of Nitrogen = N × 1 = 14 × 1 = 14 g.mol⁻¹
Molar Mass of (NH₄)H₂PO₄ = 115.03 g.mol⁻¹
Mass %age = Mass of N / M.Mass of (NH₄)H₂PO₄ × 100
Mass %age = 14 g.mol⁻¹ / 115.03 g.mol⁻¹ × 100
Mass %age = 12.17 %
In NH₃:
Mass of Nitrogen = N × 1 = 14 × 1 = 14 g.mol⁻¹
Molar Mass of NH₃ = 132.14 g.mol⁻¹
Mass %age = Mass of N / M.Mass of NH₃ × 100
Mass %age = 14 g.mol⁻¹ / 17.03 g.mol⁻¹ × 100
Mass %age = 82.20 %
In NH₄NO₃:
Mass of Nitrogen = N × 2 = 14 × 2 = 28 g.mol⁻¹
Molar Mass of NH₄NO₃ = 80.04 g.mol⁻¹
Mass %age = Mass of N / M.Mass of NH₄NO₃ × 100
Mass %age = 28 g.mol⁻¹ / 80.04 g.mol⁻¹ × 100
Mass %age = 34.98 %
