Question

How many hydrogen atoms are present in 2.00mg of aspartame

Answer 1

2.167*10^22 atoms of hydrogen

Answer 2

Answer:

$7.37\times 10^{19}$ number of H atoms are present in 2.00 mg of aspartame

Explanation:

Molecular formula of aspartame is $C_{14}H_{18}N_{2}O_{5}$

So, 1 molecule of aspartame contains 18 atoms of H

Molar mass of aspartame = 294.307 g/mol

Number of moles = (mass)/(molar mass)

So, 2.00 mg of aspartame = $\frac{2.00\times 10^{-3}}{294.307}$ moles of aspartame

We know, 1 mol of a particle = $6.023\times 10^{23}$ number of particle

So, number of molecules of aspartame in $\frac{2.00\times 10^{-3}}{294.307}$ moles of aspartame = $\frac{2.00\times 10^{-3}}{294.307}\times 6.023\times 10^{23}$

So number of H atoms in $\frac{2.00\times 10^{-3}}{294.307}$ moles of aspartame = $\frac{2.00\times 10^{-3}}{294.307}\times 6.023\times 10^{23}\times 18$ = $7.37\times 10^{19}$