Stoichiomety:
1 moles of C + 1 mol of O2 = 1 mol of CO2
multiply each # of moles times the atomic molar mass of the compund to find the relation is weights
Atomic or molar weights:
C: 12 g/mol
O2: 2 * 16 g/mol = 32 g/mol
CO2 = 12 g/mol + 2* 16 g/mol = 44 g/mol
Stoichiometry:
12 g of C react with 32 g of O2 to produce 44 g of CO2
Then 18 g of C will react with: 18 * 32/ 12 g of Oxygen = 48 g of Oxygen
And the result will be 12 g of C + 48 g of O2 = 60 g of CO2.
You cannot obtain 72 g of CO2 from 18 g of C.
May be they just pretended that you use the law of consrvation of mass and say that you need 72 g - 18g = 54 g. But it violates the proportion of C and O2 in the CO2 and is not possible.
In general the inter- molecular attraction between particles of gases is much more smaller than those found in the particles of liquids. Because of this, the particles of gases are usually far apart from one another while the particles of liquid are closer together compares to that of gases.
Answer:
water evaporate from surfaces
Explanation:
after it clumps to air to make clouds ,cools turn to liquid and rains or precipitate and becomes runoff
Answer:
Explanation:
1. Cu(NO3)2 + 2NaOH → Cu(OH)2 + 2NaNO3
2. FeSO4 + 2 NaOH = Fe(OH)2 + Na2SO4
3. Fe(NO3)3 + 3 NaOH = Fe(OH)3 + 3 NaNO3
For the second part of 3 since it tells us NaOH is excess we dont care about it. We use our balanced equation 3 to get the correct molar ratios to solve this.
1.5mol Fe(NO3)3 x 3mol NaNO3/1mol Fe(NO3)3 x 84.99gNaNO3/1molNaNO3
= 382.455g NaNO3