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3 years ago

Rate = K[A]

Chemistry

1 answer:

Aleks [24]3 years ago

8 0

Answer:

9 × 10⁻³ mol·L⁻¹s⁻¹

Explanation:

Data:

k = 1 × 10⁻³ L·mol⁻¹s⁻¹

[A] = 3 mol·L⁻¹

Calculation:

rate = k[A]² = 1 × 10⁻³ L·mol⁻¹s⁻¹ × (3 mol·L⁻¹)² = 9 × 10⁻³ mol·L⁻¹s⁻¹

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What is the freezing point of a solution of 498mL of water (solute) dissolved in 2.50 L of ethanol (solvent), C2H5OH? The densit

jok3333 [9.3K]

Answer:

Freezing T° of solution is -142.4°C

Explanation:

This excersise is about colligative properties, in this case freezing point depression,

ΔT = Kf . m . i

Where ΔT = Freezing T° of solvent - Freezing T° of solution

Kf = Cryoscopic constant

m = mol/kg (molality)

i = Number of ions dissolved.

Water is not ionic, so i = 1

Let's find out m.

We determine mass of water, by density

498ml . 1 g/mL = 498 g

We convert the mass of water to moles → 498 g . 1mol/18g = 27.6 moles

We determine mass of solvent by density

2500 mL . 0.789 g/mL = 1972.5 g

Notice, we had to convert L to mL to cancel units.

1 cm³ = 1 mL

We convert the mass from g to kg → 1972.5 g . 1kg /1000g = 1.97kg

We determine m = mol/kg → 27.6mol / 1.97kg = 13.9 m

Kf for ethanol is: 1.99 °C/m

Freezing T° for ethanol is: -114.6°C

We replace at formula: - 114.6°C - Freezing T° solution = 1.99 °C/m . 13.9 m . 1

- 114.6°C - Freezing T° solution = 27.8 °C

- Freezing T° solution = 27.8°C + 114.6°C

Freezing T° Solution = - 142.4 °C

7 0

2 years ago

Convert 798.2 g/m' to kg/cm' using dimensional analysis.

Katyanochek1 [597]

Answer:

798.2 grams / meter = 0.008 kilograms / centimeter

Explanation:

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3 years ago

What is the symbol of the new atom?<br><br>Also, is the atomic number 86?

katrin [286]

Answer:

Explanation:

Rn is the symbol for radon with the atomic number of 86

7 0

3 years ago

PLEASE HELP FOR THIS ASSIGNMENT

mars1129 [50]

<h2>Steps:</h2>

Remember that Density = mass/volume, or D = m/v

So firstly, we have to find the volume of the rock. To do this, we need to subtract the volume of water A from the volume of the water B. In this case:

Water A = 30 mL
Water B = 40 mL
40 mL - 30 mL = 10 mL

<u>The volume of the rock is 10 mL.</u>

Now that we have the volume, we can plug that and the density of the rock into the density equation to solve for the mass.

$3.678=\frac{m}{10}$

For this, multiply both sides by 10:

$36.78=m$

<h2>Answer:</h2>

<u>Rounding to the tenths place, the mass of the rock is 36.8 g, or C.</u>

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3 years ago

Would you expect Nio to dissolve in an aqueous solution of NaNO3?

Doss [256]

Answer:

NiO Does Not Dissolve In An Aqueous Solution Of NaNO3.

Explanation:

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3 years ago