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Alborosie
3 years ago
5

Isla has piano class 3 days a week. Cora has 2 times as many po

Mathematics
1 answer:
Georgia [21]3 years ago
8 0

Answer:

6

Step-by-step explanation:

no of classes isla has: 3

no of classes Cora has: 3X2

=6

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Suppose that the length of a side of a cube X is uniformly distributed in the interval 9
Nastasia [14]

Answer:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

Step-by-step explanation:

Given

9 < x < 10 --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

v = x^3

For a uniform distribution, we have:

x \to U(a,b)

and

f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.

9 < x < 10 implies that:

(a,b) = (9,10)

So, we have:

f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Solve

f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Recall that:

v = x^3

Make x the subject

x = v^\frac{1}{3}

So, the cumulative density is:

F(x) = P(x < v^\frac{1}{3})

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right. becomes

f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.

The CDF is:

F(x) = \int\limits^{v^\frac{1}{3}}_9 1\  dx

Integrate

F(x) = [v]\limits^{v^\frac{1}{3}}_9

Expand

F(x) = v^\frac{1}{3} - 9

The density function of the volume F(v) is:

F(v) = F'(x)

Differentiate F(x) to give:

F(x) = v^\frac{1}{3} - 9

F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}

F'(x) = \frac{1}{3}v^{-\frac{2}{3}}

F(v) = \frac{1}{3}v^{-\frac{2}{3}}

So:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

8 0
2 years ago
How do you do this problem
Sliva [168]

Answer:


Step-by-step explanation:

sec= x

cross multiply

60 mb x 2

120 mb/29 sec

6 0
3 years ago
A dice shows a number one through 12 which one number showing each time to die is rolled what is the probability of rolling a se
gulaghasi [49]

Answer:

1/12

Step-by-step explanation:

7 is one number out of 12 so if we take the one to the fraction is 1/12 aka simple easy math. if you want to simplify it would be impossible because 1 to 12 its impossible if it was 2/12 it would be 1/6, Sorry if i got the answer wrong.

8 0
3 years ago
Determine whether the following series converges or diverges using the integral test. Be sure to verify that the integral test c
Finger [1]

By using the integral test, series converges

What is an integral test for convergence and divergence?

⇒ It is used to prove the divergence or convergence of series. This test is called the integral test, which compares an infinite sum to an improper integral. It is important to note that this test can only be applied when we are considering a series whose terms are all positive.

How to know if a series is converging or diverging?

If the limit exists and is a finite number (a number less than infinity), we say the integral converges. If the limit is ±∞ or does not exist, we say the integral diverges.

let aₓ= f (x) is any function

⇒ In order for the integral test to work The function must be positive it has to be continuous and it has to be decreasing when x≥1

If the integral converges it means the series is also converging

If the integral diverges it means the series is also diverging

The sequence k^{3} /{e^{k^{4} } is clearly positive and decreases for k∈N then by the integral test,

\int\limits^\infty_1 {x^{3} /e^{x^4} dx \leq\displaystyle \sum^{\infty}_{k = 1} {x^{3} /e^{x^{4}

and

\int\limits^\infty_1 {x^{3} /e^{x^4} dx=1/4\int\limits^\infty_1 {x^{3} /e^{-u} du

⇒ 1/4 < \infty

So it comes with a finite value hence the series converges

Learn more about the integral tests here :

brainly.com/question/15394015

#SPJ1

4 0
1 year ago
Read 2 more answers
Missy started with $217 in her bank account. She deposits $25.50 each week and never withdraws any money. What expression can Mi
JulijaS [17]

Answer: yep

Step-by-step explanation:

4 0
3 years ago
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