Ask question

Ask question

All categories

AleksAgata [21]

3 years ago

15

Calculate the product in square (m2)

1 answer:

Jet001 [13]3 years ago

4 0

$1m=100cm\to1cm=\dfrac{1}{100}m\\\\1dam=10m\\\\\text{therefore}\\\\\dfrac{2}{5}cm=\dfrac{2}{5}\cdot\dfrac{1}{100}m=\dfrac{1}{250}m\\\\\dfrac{1}{3}dam=\dfrac{1}{3}\cdot10m=\dfrac{10}{3}m\\\\\dfrac{2}{5}cm\times\dfrac{1}{3}dam=\dfrac{1}{250}m\times\dfrac{10}{3}m=\dfrac{1}{75}m^2$

You might be interested in

Help me please (I need write more something in order to I can submit answer)

Nataly_w [17]

Answer:

The answer is 4

Step-by-step explanation:

(-2.4)(10) / -3(2)

-24/-6

=4

8 0

2 years ago

Read 2 more answers

Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

3 years ago

Polygon ABCDE is the first in a pattern for a high school art project. The polygon is transformed so that the image of A’ is at

djyliett [7]

Answer:

4.21

Step-by-step explanation:

Because 2.1 is also equivalent to -4.2 which also is equivalent to D'.

7 0

3 years ago

max's stamp collection has stamps for different countries.he has 12 stamps from canada.of those tweleve,2/3 of them have picture

solong [7]

8 stamps. Multiply 2/3 by 12 and you have your answer

3 0

3 years ago

Read 2 more answers

Halp mi now. pls<br> pls plsp lls plsp pls

Thepotemich [5.8K]

Answer:

-r+5<-3

Step-by-step explanation:

plug in 19 to the equation inequality

7 0

2 years ago