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aniked [119]
4 years ago
11

Solve for b in (y^-9)^b=y^45

Mathematics
1 answer:
ElenaW [278]4 years ago
8 0
Y^-9 * b = y^45   Divide by y^-9
b = \dfrac{y^{45}}{y^{-9}}

The law of powers says that if you have the same base (y in this case) and two different powers that are divided, you can subtract the denominator from the numerator (in this case)

b = y^{45- - 9} = y^{54}
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Find 3 different ratios that are equivalent to 7:3.
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Answer:

14:6

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28:12

Step-by-step explanation:

Given the initial ratio of 7:3, you can find equivalent ratios by multiplying the two numbers by the same factor:

7 x 2 = 14

3 x 2 = 6

14:6

7 x 3 = 21

3 x 3 = 9

21:9

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3 years ago
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Answer:

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Step-by-step explanation:

1st boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a

Equation:

y=ax^2 -2ax+c

The y-coordinate of the vertex:

y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1

Solve:

c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}

Parabola equation:

y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}

2nd boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0

Equation:

y=ax^2+c

The y-coordinate of the vertex:

y_v=a\cdot 0^2+c\Rightarrow c=-7

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-7\\ \\64a-7=1

Solve:

a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7

Parabola equation:

y=\dfrac{1}{8}x^2 -7

System of two equations:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

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Answer:

Step-by-step explanation:

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