Question

An experiment is completed where a coin is flipped and a six-sided die (singular for dice) is rolled. The outcomes from the experiment are shown, where H represents heads and T represents tails. H1, H2, H3, H5, H6, T1, T1, T2, T3, T5. What percent of the outcomes included tails with an off number greater than 1? 1.) 16 2/3% 2.) 25% 3.) 33 1/3% 4.) 41 2/3%

Answer 1

Answer:

1) $16\frac{2}{3}$% or 20%

Step-by-step explanation:

Given that:

An experiment which is carried out by flipping a coin and rolling six sided die.

The outcomes can be:

{H1, H2, H3, H5, H6, T1, T1, T2, T3, T5}

As per question statement:

Number of outcomes having tails and an odd number greater than one is 2 (i.e. T3 and T5)

Total number of outcomes here is 10.

Therefore, to find the percentage, we use the following formula:

$\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\times 100$

$\Rightarrow \dfrac{2}{10}\times 100 = 20\%$

As per question statement, the answer is 20%.

If we consider all the outcomes, i.e.

{H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}

Total number of outcomes = 12

The percentage will come out be :

$\Rightarrow \dfrac{2}{12}\times 100 = 16\frac{2}{3}\%$