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dem82 [27]
3 years ago
14

The diagonals of a rectangle are always perpendicular. A)True B)False

Mathematics
1 answer:
goblinko [34]3 years ago
4 0

Answer:

Step-by-step explanation:

False. If L does not equal W the diagonals are not perpendicular. If L=W then they are perpendicular but that is a square and a special case which is not always true of a rectangle.

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Tuto
alexgriva [62]

answer is 40%

hope it helped you

8 0
2 years ago
3(q−7)=27 need help plzz 1st peep gets brainlest
ANTONII [103]

━━━━━━━☆☆━━━━━━━

▹ Answer

<em>q = 16</em>

▹ Step-by-Step Explanation

3(q - 7) = 27

3q - 21 = 27

Add 21 to both sides:

21 + 21 = na

27 + 21 = 48

3q = 48

Divide both sides by 3:

3/3 = q

48/3 = 16

q = 16

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

8 0
4 years ago
Read 2 more answers
Equations<br> Solve T = C(9+ AB) for B
MaRussiya [10]

Answer:

Simplifying

T = C(9 + AB) * forB

Reorder the terms for easier multiplication:

T = C * forB(9 + AB)

Multiply C * forB

T = forBC(9 + AB)

T = (9 * forBC + AB * forBC)

Reorder the terms:

T = (forAB2C + 9forBC)

T = (forAB2C + 9forBC)

Solving

T = forAB2C + 9forBC

Solving for variable 'T'.

Move all terms containing T to the left, all other terms to the right.

Simplifying

T = forAB2C + 9forBC

Step-by-step explanation:

Simplifying

T = C(9 + AB) * forB

Reorder the terms for easier multiplication:

T = C * forB(9 + AB)

Multiply C * forB

T = forBC(9 + AB)

T = (9 * forBC + AB * forBC)

Reorder the terms:

6 0
2 years ago
4. Calculate the product of 8/15, 6/5, and 1/3.
RSB [31]
A because the 6 and 3 cancel out
Then 2 x 8 is (16) and 15 x 5 is (75)
Making it A
6 0
3 years ago
Read 2 more answers
Solve for x and y
bekas [8.4K]

Answer:

x = 2√2

y = 2√6

Step-by-step explanation:

Consider the ratio of the two legs of the two smaller interior right triangles. (refer to attached diagrams for the triangles - I have outlined one in blue and the other in red)

These will be equal since the triangles are similar

shorter leg : longer leg

(blue triangle = red triangle)

⇒ x : 4 = 2 : x

⇒ x/4 = 2/x

⇒ x² = 8

⇒ x = √8

⇒ x = 2√2

Now we have x, we have the two legs of the right triangle with hypotenuse labelled y.

Using Pythagoras' Theorem a² + b² = c² (where a and b are the legs and c is the hypotenuse)

⇒ 4² + (2√2)² = y²

⇒ y² = 24

⇒ y = √24

⇒ y = 2√6

7 0
2 years ago
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