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Lilit [14]
3 years ago
7

Two different equations can never have the same answer​

Mathematics
2 answers:
taurus [48]3 years ago
5 0

Answer:

It's false  

Step-by-step explanation:

because there are many different equations that have same answers.

Kobotan [32]3 years ago
3 0

Answer:

false

Step-by-step explanation:

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Find the midpoint M of the line segment joining the points A = (-5, 7) and B = (-1, -5).
11111nata11111 [884]

Answer:

M = (-3,1)

Step-by-step explanation:

We need to find the midpoint M of the line segment joining the points

A = (-5,7) and B = (-1, -5)

The mid point of the line segment joining the points (x₁,y₁) and (x₂,y₂) is given by :

M=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})\\\\M=(\dfrac{-5+(-1)}{2},\dfrac{7+(-5)}{2})\\\\M=(-3,1)

Hence, the required point is (-3,1).

6 0
3 years ago
I'm a little bit confused about how to approach this can someone help?
Taya2010 [7]

Answer:

4

Step-by-step explanation:

ΔABC is congruent with ΔDEF.  That means the corresponding sides are congruent.

Look at the order of the letters.  EF are the last two letters of ΔDEF.  So this corresponds with the last two letters of ΔABC.  Therefore, EF ≅ BC.

EF ≅ BC

x² + 8x = 48

x² + 8x − 48 = 0

(x + 12) (x − 4) = 0

x = -12 or 4

Since x can't be negative, x = 4.

5 0
3 years ago
Please help me on this question.
Kay [80]

Answer:

3×(27-7) says to subtract 7 from 27 first, then multiply with 3; but 3×27-7 says to multiply 3 by 27 first ,then subtract 7.

The second bullet is the correct option

7 0
4 years ago
Given that A and B are true and X and Y are false, determine the truth value of the following proposition: ~[(A ⊃ Y) v ~(X ⊃ B)]
Anni [7]

Answer:

The value of the proposition is FALSE

Step-by-step explanation:

~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ ~X) v (B ⊃ X)]

Let's start with the smallest part: ~X. The symbol ~ is negation when X is true with the negation is false and vice-versa. In this case, ~X is true (T)

~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ T) v (B ⊃ X)]

Now the parts inside parenthesis:  (A ⊃ Y),(X ⊃ B),(A ≡ T) and (B ⊃ X). The symbol ⊃ is the conditional and A ⊃ Y is false when Y is false and A is true, in any other case is true. The symbol ≡ is the biconditional and A ≡ Y is true when both A and Y are true or when both are false.

(A ⊃ Y) is False (F)

(X ⊃ B) is True (T)

(A ≡ T) is True (T)

(B ⊃ X) is False (F)

~[(F) v ~(T)] ⋅ [~(T) v (F)]

The two negations inside the brackets must be taken into account:

~[(F) v F] ⋅ [F v (F)]

The symbol left inside the brackets v is the disjunction, and A v Y is false only  with both are false. F v (F) is False.

~[F] ⋅ [F]

Again considerating the negation:

T⋅ [F]

Finally, the symbol ⋅ is the conjunction, and A v Y is true only with both are true.

T⋅ [F] is False.

5 0
3 years ago
Is -6 greater than -3??
densk [106]

Answer:

No.

Step-by-step explanation:

-3 is greater than -6. I Hope this helps. Im trying to level up so I'd appreiciate it if you marked me as brainliest. Thank you!

7 0
3 years ago
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