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KonstantinChe [14]
2 years ago
14

What is the radius of the circle whose equation is x^2 + y^2 = 8

Mathematics
1 answer:
gogolik [260]2 years ago
5 0
√8

for the equations of circles: x²+y²= (radius)²
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PLEASE HURRY. <br> 24. Factor completely<br> (1 Point<br> 14x^3 – 16x^2 + 21x – 24
Inessa05 [86]

Answer:

(7x - 8)(2x² + 3)

Step-by-step explanation:

Given

14x³ - 16x² + 21x - 24 ( factor the first/second and third/fourth terms )

= 2x²(7x - 8) + 3(7x - 8) ← factor out (7x - 8) from each term

= (7x - 8)(2x² + 3)

7 0
3 years ago
P(2,-8), Q(8,-8), R(8, -2), S(2,-2)<br> 180° rotation<br> I need help quickly
kompoz [17]

Answer:

P(-2,8)   Q(-8,8)   R(-8,2)  S(-2,2)

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3 years ago
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4 0
2 years ago
8 freshmen, 9 sophomores, 9 juniors, and 7 seniors are eligible to be on a committee.
loris [4]

Answer: 11113200

Step-by-step explanation:

We know that , the number of combination of choosing r things from n things is given by :-

^nC_r=\dfrac{n!}{r!(n-r)!}

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

^8C_4\times ^9C_5\times^9C_2\times^7C_3

=\dfrac{8!}{(8-4)!4!}\times\dfrac{9!}{(9-5)!5!}\times\dfrac{9!}{(9-2)!2!}\times\dfrac{7!}{3!(7-3)!}\\\\ =\dfrac{8\times7\times6\times5\times4!}{4!4!}\times\dfrac{9\times8\times7\times6\times5!}{4!5!}\times\dfrac{9\times8\times7!}{7!2!}\times\dfrac{7\times6\times5\times4!}{3!4!}\\\\=11113200

∴ The number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors = 11113200

6 0
3 years ago
49 POINTS!!!!!!!!
belka [17]
The answer is II and III, which is the last choice from above.  This is because the symbol "less than (or equal to)" indicated a conjunction, which means we have to take into account that the absolute value can be less than or equal to 15, and greater than or equal to -15.  This solution set falls in between the two values, hence, the conjunction.
3 0
3 years ago
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