Answer:
f(2) = -2
Step-by-step explanation:
plug in 2 to wherever x is in this statement:
f(2) = -2(2^2) - 2(2) + 10
f(2) = -2(4) - 4 + 10
f(2) = -8 - 4 + 10
f(2) = -2
You can write it in the form a^2 - b^2 where a = 5x and b = p
(5x)^2 - p^2
And then use the Difference of Squares a^2 - b^2 = (a + b)(a - b)
Answer is (5x + p)(5x - p)
Answer: D.
Step-by-step explanation:
For an absolute value function, the vertex of
is defined as the point (-h, k) for the coordinate (x, y).
When x is equal to negative h, the value for x and value for h effectively cancel out, and only the positive k remains, hence the vertex being (-h, k).
The function given has a vertex at (2, 3). We know that the vertex of an absolute function is (-h, k), so h must equal -2 and k must equal 3.
The equation:

since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
Answer:
i dont know
Step-by-step explanation: