Dimensions are length 20 meter and width 14 meter
<em><u>Solution:</u></em>
Let "a" be the length of rectangle
Let "b" be the width of rectangle
Given that,
<em><u>A rectangle has width that is 6 meters less than the length</u></em>
Width = length - 6
b = a - 6
The area of the rectangle is 280 square meters
<em><u>The area of the rectangle is given by formula:</u></em>

<em><u>Substituting the values we get,</u></em>

<em><u>Solve the above equation by quadratic formula</u></em>



Since, length cannot be negative, ignore a = -14
<em><u>Thus solution of length is a = 20</u></em>
Therefore,
width = length - 6
width = 20 - 6 = 14
Thus dimensions are length 20 meter and width 14 meter
Answer:
5740
Step-by-step explanation:
Answer:
A(7,5)
Step-by-step explanation:
This is correct because the area of a triangle is b × h = a.
Answer:
C.
Step-by-step explanation:
2x-10/x-3=5/3 X=15
Answer:
m < 2 = 137°
m < 4 = 137°
Step-by-step explanation:
Given that m < 7 = 43°, we can say that it has the same measure as < 3 because they are corresponding angles. Thus, we can establish that m < 3 = 43°.
We can use m < 3 = 43° to find m < 4, as they are supplementary angles that have a sum of 180°.
Therefore:
m < 3 + m < 4 = 180°
Rearrange the formula to isolate m < 4:
m < 4 = 180° - m < 3
Substitute the value of m < 3 into the rearranged formula:
m < 4 = 180° - m < 3
m < 4 = 180° - 43°
m < 4 = 137°
Therefore, m < 4 = 137°.
< 2 and < 4 also have the same measure because they are vertical angles. Two angles are vertical angles if they are opposite angles formed by the intersection of two lines.
Hence, m < 2 = 137°
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