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Sauron [17]
2 years ago
12

Please help again ASAP!!! I appreciate answers!

Mathematics
1 answer:
Natalija [7]2 years ago
5 0

Answer

The answer would be the second one!

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HELPP PLEASE
umka21 [38]

Answer:

27.5 mm

Step-by-step explanation:

The game piece has the shape of two identical square pyramids attached at their bases. Given that the perimeters of the square bases are 80 millimeters, and the slant height of each pyramid is 17 millimeters.

Let the side length of each of the side of the base of the pyramid be b, hence:

perimeter = 4b

80 = 4b

b = 20 mm. half of the side length = b/2 = 20 / 2 = 10 mm

The slant height (l) = 17 mm, Let h be the height of one of the pyramid, hence, using Pythagoras theorem:

(b/2)² + h² = l²

17² = 10² + h²

h² = 17² - 10² = 189

h = √189

h = 13.75 mm

The length of the game piece = 2 * h = 2 * 13.75 = 27.5 mm.

6 0
3 years ago
Braden logged 3 2/3 hours last week in his reading journal and 2 3/6 hours last week how many fewer hours did Brayden log in his
lubasha [3.4K]

Answer:

1 1/6

Step-by-step explanation:

im guessing you need this fast so i wont explain it

5 0
2 years ago
The equations in this sytem were added to solve for x. What is the value of x?
son4ous [18]

<em><u>Question:</u></em>

The equations in this system were added to solve for x. What is the value of x? -2x+y=8 5x-y=-5 3x=3

Options:

x = negative 3

x = negative 1

x = 1

x = 3

<em><u>Answer:</u></em>

The value of x is 1

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

-2x + y = 8 ------- eqn 1

5x - y = -5 ------- eqn 2

The above equations are added to solve for "x"

Add eqn 1 and eqn 2

-2x + y + 5x - y = 8 - 5

Combine the like terms

-2x + 5x + y - y = 3

Add the like terms

3x + 0 = 3

3x = 3

Divide both sides of equation by 3

x = 1

Thus the value of x is 1

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2 years ago
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11000 or 594+1111 jobs India knacks ka insisss
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The table shows the annual increase in cost in t years for certain grocery items. Based on the formula A = C(1 + r)t, which equa
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C is the answer to your question
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