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garri49 [273]
3 years ago
12

Simplify 7 (2x + 4) + 14.

Mathematics
1 answer:
bearhunter [10]3 years ago
6 0

Answer: 14x + 42

7(2x+4)+14

14x + 28 + 14

<u>14x + 42</u>

Step-by-step explanation:

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Given z1 = startroot 2 endroot (cosine (startfraction 3 pi over 4 endfraction) i sine (startfraction 3 pi over 4 endfraction) )
vampirchik [111]

The subtraction of complex numbers z_{1} -z_{2} is cos(π)+i sin(π).

Given z_{1} =\sqrt{2}[cos(3π/4+i sin(3π/4) and z_{2}=cos (π/2) +i sin(π/2)

We have to find the value of z_{1} -z_{2}.

A complex number is a number that includes real number as well as a imaginary unit in which i^{2} =1. It looks like a+ bi.

We have to first solve z_{1} and z_{2} and then we will be able to find the difference.

z_{1} =\sqrt{2}[ cos (3π/4)+i sin (3π/4)]

=\sqrt{2}[cos(π-π/4)+ i sin (π-π/4)]

=\sqrt{2} [-cos(π/4)+sin (π/4)]

=\sqrt{2}(-1/\sqrt{2}+1/\sqrt{2})

=\sqrt{2} *0

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z_{2} =cos(π/2)+i sin (π/2)

=0+i*1

=1

Now putting the values of z_{1}  and z_{2},

z_{1} -z_{2} =0-1

=-1

=-1+i*0

=cos (π)+i sin(π)

Hence the value of difference between z_{1} and z_{2} is cos(π)+i sin(π).

Learn more about complex numbers at brainly.com/question/10662770

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