Question

X^2-16/x^2-3x-4 simply

Answer 1

Answer:

x+4/x+1

Step-by-step explanation:

hope this can help you :)

Answer 2

Answer:

$\frac{x+4}{x+1}$

Step-by-step explanation:

Given

$\frac{x^2-16}{x^2-3x-4}$ ← factor numerator/ denominator

= $\frac{(x-4)(x+4)}{(x-4)(x+1)}$ ← cancel the factor (x - 4) on numerator/ denominator

= $\frac{x+4}{x+1}$