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Serhud [2]
2 years ago
8

X^2-16/x^2-3x-4 simply

Mathematics
2 answers:
kolbaska11 [484]2 years ago
7 0

Answer:

x+4/x+1

Step-by-step explanation:

hope this can help you :)

Makovka662 [10]2 years ago
4 0

Answer:

\frac{x+4}{x+1}

Step-by-step explanation:

Given

\frac{x^2-16}{x^2-3x-4} ← factor numerator/ denominator

= \frac{(x-4)(x+4)}{(x-4)(x+1)} ← cancel the factor (x - 4) on numerator/ denominator

= \frac{x+4}{x+1}

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