Question

What is an equation in point- slope form for the line perpendicular to y= 3x-4 that contains (7,2)?

Answer 1

Answer:

y - 2 = - $\frac{1}{3}$ (x - 7)

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 4 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

$\frac{m}{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{3}$

The equation of a line in point- slope form is

y - b = m(x - a)

m is the slope and (a, b) a point on the line

Here m = - $\frac{1}{3}$ and (a, b) = (7, 2), thus

y - 2 = - $\frac{1}{3}$(x - 7) ← equation of perpendicular line