Answer:
8^-2a^7 = a^7/8^2 = a^7/64
Step-by-step explanation:
Hey there!
Our function is:
f(x) = 4^x
If we want to have f(3), we simply can plug in 3 to our answer, and evalutate from there:
f(x) = 4^3 =
4*4*4 =
16*4 =
64
We just calculated 4 to the fourth power, which is four times four times four times four. Therefore, 4 of four is equal to 64.
Hope this helps!
{{{ THE BOLDED CHARACTERS SHOULD BE SMALL. }}}
SEQUENCE: 6, 18, 54, 162
18/6 = 3
54/18 = 3
162/54 = 3
then, r (common ratio) = 3
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RECURSIVE RULE: r = 3
an = a(n - 1) × r [formula]
ANSWER: an = a(n - 1) × 3
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ITERIATIVE RULE: r = 3, a1 = 6
an = a1 × r^(n - 1) [formula] [ ^(n-1) is an exponent]
ANSWER: an = 6 × 3^(n - 1)
Answer: 
<u>Step-by-step explanation:</u>
2x^2 + x -3 can be factorised
<span>[2x + 3][x - 1] </span>
<span>As length times width = area </span>
<span>one possible set of measurements are </span>
<span>length = [2x + 3] </span>
<span>width = [x-1] </span>
