The frist line may be one with the numbers 0, 1 and 2 and 10 divisions (marks at equal distance) between each integer. Each division will be equal to 0.1 units and then you can mark the second division from the zero point to the right as the 0.20 mark.
The other line must have the same integers, 0 , 1 and 2 placed in identical form as the first line. Then
- draw an inclined straight line since the point zero,
- mark 5 points in the inclined lined equally spaced over the line.
- draw a sttraight line from the 5th point to the point with the mar 1 over the base number line.
- draw a parallel line to the previous one passing trhough the second point of the inclined line and mark the point where this parallel touchs the base number line. This point shall be at the same distance from zero than the 0.2 mark was in the first number line, meaning that 0.2 and 1/5 are equivalent.
4x^2-3x+4y^2+4z^2=0
here we shall proceed as follows:
x=ρcosθsinφ
y=ρsinθsinφ
z=ρcosφ
thus
4x^2-3x+4y^2+4z^2=
4(ρcosθsinφ)^2-3(ρcosθsinφ)+4(ρsinθsinφ)^2+4(ρcosφ)
but
ρ=1/4cosθsinφ
hence we shall have:
4x^2-3x+4y^2+4z^2
=1/4cosθsinθ(cosθ(4-3sinφ))+4sin^2(φ)
1 /million is the chance
1/1,000,000 or in decimals 0.000001 is the chance
Answer is = X^6
Please give me the brainliest
The equation would be 30+3m=162 then you solve the problem
