Answer:
120
240
Step-by-step explanation:
We call the length of first part x
Length of second part = y
In the first scenario, it took the tortoise 110 sec to walk the first part and crawl the second.
So,
We have this equation,
x/4 + y/3 = 110
We take the LCM
(3x + 4y)/12 = 110
When we cross multiply
3x + 4y = 110x12
3x + 4y = 1320 ----- equation 1
For scenario 2
x/3 + y/4 = 100
When we take the LCM
(4x + 3y)/12 = 100
We cross multiply
4x + 3y = 100x12
4x + 3y = 1200 ------ equation 2
We now have two equations and we will solve for x and y using simultaneous linear equation.
3x + 4y = 1320 ----- 1
4x + 3y = 1200 ----- 2
We subtract equation 2 from 1 to get
- x + y = 120
We make y subject
y = x + 120 ----- 3
We put the value of y in equation 3 into equation 1
3x + 4(x + 120) = 1320
3x + 4x + 480 = 1320
7x + 480 = 1320
7x = 1320-480
7x = 840
We divide through by 7
x = 840/7
x = 120
We put value of x in equation 3
y = x + 120
y = 120 + 120
y = 240
120 and 240 are the lengths of the 2 parts of the journey.
Thanks
Answer:
4x^2
Step-by-step explanation:
The greatest common factor is the greatest number that can divide the terms. The greatest number that can divide each term is 4, and the greatest power of x that can divide each term is x^2. This is because it can't be any number greater than 4 since that number would never be able to divide into 4. This is also the reason why x^2 is the greatest power possible. It cannot be greater than anything divisible by itself. Thus, you multiply 4 by x^2 and the answer is 4x^2.
Answer:
slope = 2
Step-by-step explanation:
Calculate the slope m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (1, 3) and (x₂, y₂ ) = (4, 9)
m =
=
= 2
Answer:
To find the LCD of two rational expressions, we factor the expressions and multiply all of the distinct factors. For instance, if the factored denominators were (x+3)(x+4) ( x + 3 ) ( x + 4 ) and (x+4)(x+5) ( x + 4 ) ( x + 5 ) , then the LCD would be (x+3)(x+4)(x+5) ( x + 3 ) ( x + 4 ) ( x + 5 ) .
Answer:
2a
Step-by-step explanation:
using distance formula:
√(x₂-x₁)² + (y₂-y₁)²
putting values,
√{a-(a)}² + {b-b}² = √ {a+a}² + 0²
= √(2a)² = √4a² = 2a
Hope this helps:)