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lara31 [8.8K]
2 years ago
9

Which three lengths could be the lengths of a triangle?

Mathematics
1 answer:
attashe74 [19]2 years ago
8 0

Answer: number one is d and number 3 is c I think

Step-by-step explanation:

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I need the answer fast please​
Rainbow [258]
Substitute each value of x in y=2x-3

so,

first box (-2)
y= 2(-2)-3
y= -4-3
y= -7

second box (0)
y= 2(0)-3
y= 0-3
y= -3

third box (3)
y=2(3)-3
y=6-3
y=3
6 0
2 years ago
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Find 12 +13 - (-9)+(-19.4) +3.3
Rina8888 [55]

Answer:

17.9

Step-by-step explanation:

You could use PEMDAS but you don't really need to because this is just adding an subtracting.

5 0
3 years ago
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ANY MATH EXPERTS PLS HELP RN I GOT 30 MIN LEFT I'll MARK BRAINLIEST TO WHO ANSWER'S FIRST
garri49 [273]

Answer:

y = -1/4x - 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from the graph.</em>

Point (-4, -5)

y-intercept (0, -6)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{-6+5}{0+4}
  2. Add:                              m=\frac{-1}{4}

<u>Step 3: Write linear function</u>

y = -1/4x - 6

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3 years ago
Please help pic attatched i will give brainliest
Alchen [17]

Answer:

N'(x)=90 In(43)*43^x-90 In(50)*43^x /50^x

Step-by-step explanation:

4 0
2 years ago
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the third term of an arithmetic sequence is 24 and the fifth is 32 if the first term is a1. which is an equation nth term of the
const2013 [10]
An = a1 + (n - 1)(d)
Where a1 is the first term and d is the common difference.
First find d, the common difference.
24, ____, 32
a3 a4 a5
Subtract 32-24 = 8
Subtract a5 - a3 = 2
Divide 8/2 = 4
d = 4
Use d and one of the values they give us to find a1.
a3 = 24
24 = a1 + (3 - 1)(4)
24 = a1 + 2(4)
24 = a1 + 8
Subtract 8 from both sides
16 = a1
an = 16 + (n - 1)(4)
Can also be written
an = 16 + 4n - 4
an = 4n + 12
8 0
3 years ago
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