Answer:
I think - option c. 54.22kg
Step-by-step explanation:
Answer:
12<x<16
Step-by-step explanation:
if c^2 > a^2 + b^2
then the triangle is obtuse
since 20 is the longest side
20^2 > x^2 + (x+4)^2
simplify
400 > x^2 + (x+4)(x+4)
FOIL
400 > (x^2 ) + (x^2 + 4x+4x+16)
combine like terms
400 > (2x^2 + 8x+16)
divide by 2
400/2 > 2x^2 /2 + 8x/2 + 16/2
200 > x^2 + 4x +8
subtract 200 from each side
0> x^2 + 4x +8-200
0> x^2 +4x-192
Factor
0 > (x-12) ( x+16)
using the zero product property
0> x-12 0 > x+16
12>x -16>x
x must be greater than 12
we know the longest side is 20
x+4 < 20
subtract 4
x< 16
x>12 and x < 16
12<x<16
First line because 4(2a+1)=8a+4 and 9a+4-(8a+4)= a
Second line because a times 2 =2a and 2a+1-2a=1
<span>Although the second equality is more or less obvious since 2a+1 leaves a remainder of 1 when divided by a.</span>
0.25e − 14 = 26 Then you add 14 from both sides
0.25e=40 Then you divide both sides by 0.25
e=160
Then to check you work you do this:
0.25(160)-14=26
40-14=26
26=26 Correct!!!!
<h3>
Answer: 3 m/s^2</h3>
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According to Newton's Second Law, we know that
F = m*a
where F is the force applied, m is the mass and 'a' is the acceleration.
We see that this is a direct variation equation for F and a, such that m is the constant of variation. It's similar to how y = kx is also a direct variation equation.
Plug in F = 35 and a = 5 to find m
F = ma
35 = m*5
35/5 = m
7 = m
m = 7
The object has a mass of 7 kg
Our equation F = ma updates to F = 7a
Now plug in the force F = 21 to find 'a'
F = 7a
21 = 7a
21/7 = a
3 = a
a = 3
The acceleration will be 3 m/s^2
Notice how a smaller force applied means that the acceleration has also gone down as well.
