Question

In a board game, you must roll two 6-sided number cubes. You can only start the game if you roll a 3 on at least one of the number cubes.
A) Make a list of all the different possible outcomes when two number cubes are rolled.

B) What fraction of the possible outcomes is favorable?

C) Suppose you rolled the two number cubes 100 times, would you expect at least one 3 more or less than 34 times? Explain

Answer 1

Give brainliest to other person lol. I answered ur other question on the same thing tho

Answer 2

A) You can have

1-1; 1-2; 1-3; 1-4; 1-5; 1-6; 2-2; 2-3; 2-4; 2-5; 2-6; 3-3; 3-4; 3-5; 3-6; 4-4; 4-5; 4-6; 5-5; 5-6; 6-6

Those are all possible outcomes

B) Only 6 of the options include at least one three

The fraction is: 6/21 or simplified 2/7

C) To find this answer we need a percentage

to find that...

6/21 and ?/100

(When writing put it as a fraction to visually see the next part)

We will cross-multiply: the ? will be represented by x

(6 times 100) + (21x)

600 = 21x

Now divide 600 by 21 to get about 28.6

Since 28.6 < 34 then we would get a probability of less than 34 out of 100