Answer:
d1=2A/d2
d2=2A/d1
Step-by-step explanation:
The options of this question are:
1. d₁=2Ad₂
2. d₁= 2A/d₂
3. d₂= d₁/2A
4. d₁= 2A/d₂
5. d₂= 2Ad₁
Given:
A=1/2(d1*d2)
Multiply both sides by 2
We have,
2A=d1*d2
Divide both sides by d2
2A/d2=d1*d2/d2
2A/d2=d1
Therefore, d1=2A/d2
Similarly, from the previous equation
2A=d1*d2
Divide both sides by d1
2A/d1=d1*d2/d1
2A/d1=d2
Therefore,
d2=2A/d1
Options
2. d₁= 2A/d₂
4. d₁= 2A/d₂
Answer:
my bad
The correct answer is C
Step-by-step explanation:
hopr it helps
have a great day
:)
With the equation 4x, the x represents side length. Since we are given side length of 5/7, then the equation becomes
perimeter = 4 × 5/7
p= 20/7
p= 2 6/7 units
Answer:
Domain and Range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively
Step-by-step explanation:
We have the functions, f(x) = eˣ and g(x) = x+6
So, their composition will be g(f(x)).
Then, g(f(x)) = g(eˣ) = eˣ+6
Thus, g(f(x)) = eˣ+6.
Since the domain and range of f(x) = eˣ are all real numbers and positive real numbers respectively.
Moreover, the function g(f(x)) = eˣ+6 is the function f(x) translated up by 6 units.
Hence, the domain and range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively.
First recognize that the unit rate we're finding is gallons per hour, or

.
rate for Tank 1 = x gallons per hour = <em>a</em> gallons / <em>b</em> hours

rate for Tank 2 = y gallons per hour = <em>c</em> gallons / <em>d</em> hours