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2 years ago

13

CD is a perpendicular bisector of chord AB and a chord through CD passes through the center of a circle. Find the diameter of th

e wheel.

1 answer:

Keith_Richards [23]2 years ago

5 0

Answer:

$12\frac{1}{5}$ in

Step-by-step explanation:

I don't know if you got this pic but this is the answer for this pic

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John and Samuel had a challenge. John told Samuel that 12 x 12=9. What strategy did John use to come up with his answer as 9? Ex

kondor19780726 [428]

Answer:

John added 1 +4 +4 to get 9 (12x12 = 144)

Step-by-step explanation:

12x12 actually equals 144

1 + 4 +4 = 9 so it appears John just added all the digits of 144 to get 9

8 0

2 years ago

310-(30x7)=5xk solve for k

NeX [460]

Answer K= 20/x

Step-by-step explanation:

8 0

3 years ago

The ice cream parlor serves spherical scoops of ice cream with a radius of 1 in. What is the approximate volume of 2 scoops of i

Varvara68 [4.7K]

Answer: 8.37 in³

Step-by-step explanation:

Given the following :

Shape of icre cream scoop = sphere

Radius (r) = 1 inch

Volume of a scoop of icecream = volume of sphere :

4/3πr³

(4/3) × 3.14 × 1³

1.333 × 3.14 × 1

= 4.1867 in³

Hence, the volume of 2 scoops of ice cream will be :

2 × ( volume of a scoop of ice cream)

(2 × 4.1867) in³

= 8.37 in³

6 0

2 years ago

Ayuda necesito resolver este problema con procedimiento ;)

Paraphin [41]

$x^3-2x^2+x-1$ is one of the prime factors of the polynomial

<h3>How to factor the expression?</h3>

The question implies that we determine one of the prime factors of the polynomial.

The polynomial is given as:

$x^8 - 3x^6 + x^4 - 2x^3 - 1$

Expand the polynomial by adding 0's in the form of +a - a

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^8 -2x^7 + 2x^7 - 4x^6 +x^6 + 2x^5 -2x^5- 3x^4 + 4x^4 + 2x^3 -6x^3+2x^3- x^2 -3x^2 +4x^2-2x+2x-1$

Rearrange the terms

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^8 -2x^7 + 2x^5 - 3x^4 + 2x^3 - x^2 + 2x^7 - 4x^6 + 4x^4 -6x^3+4x^2-2x+x^6-2x^5+2x^3-3x^2+2x-1$

Factorize the expression

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^2(x^6-2x^5+2x^3-3x^2+2x-1) + 2x(x^6-2x^5+2x^3-3x^2+2x-1) + 1(x^6-2x^5+2x^3-3x^2+2x-1)$

Factor out x^6-2x^5+2x^3-3x^2+2x-1

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x^2+2x + 1)(x^6-2x^5+2x^3-3x^2+2x-1)$

Express x^2 + 2x + 1 as a perfect square

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6-2x^5+2x^3-3x^2+2x-1)$

Expand the polynomial by adding 0's in the form of +a - a

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6- 2x^5+x^4-x^4-x^3 +x^3-2x^3-x^2 -2x^2 +x+x - 1)$

Rearrange the terms

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6- 2x^5+x^4-x^3-x^4-2x^3-x^2+x+x^3-2x^2 +x - 1)$

Factorize the expression

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^3(x^3-2x^2+x-1) -x(x^3-2x^2+x-1)+1(x^3-2x^2+x-1))$

Factor out x^3-2x^2+x-1

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^3 -x+1)(x^3-2x^2+x-1)$

One of the factors of the above polynomial is $x^3-2x^2+x-1$ .

This is the same as the option (c)

Hence, $x^3-2x^2+x-1$ is one of the prime factors of the polynomial

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

4 0

1 year ago

What is the solution for the system of equations?

Lena [83]

Answer:

1, 3

Step-by-step explanation:

// Solve equation [2] for the variable y

[2] y = x - 2

// Plug this in for variable y in equation [1]

[1] (x -2) + x = 4

[1] 2x = 6

// Solve equation [1] for the variable x

[1] 2x = 6

[1] x = 3

// By now we know this much :

y = x-2

x = 3

// Use the x value to solve for y

y = (3)-2 = 1

5 0

2 years ago