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JulijaS [17]
2 years ago
13

A garden is 20 feet long by 8 feet wide. The length and width of the garden will each be increased by the same number of feet. T

his expression represents the perimeter of the larger garden:
(x + 20) + (x + 8) + (x + 20) + (x + 8)
Which expression is equivalent to the expression for the perimeter of the larger garden?
Select all that apply.

A. 4x + 56

B. 2(2x + 28)

C. 2(x + 20)(x + 8)

D. 4(x + 20)(x + 8)

E. 2(x + 20) + 2(x + 8)
Mathematics
2 answers:
Kryger [21]2 years ago
8 0
The answer is C hope it helped
marta [7]2 years ago
4 0
The correct answer is C because the problem showed ( x + 20 ) and ( x + 8 ) two times in the problem. That explains why there is a two outside of the parentheses.
Hope I helped! :)
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Answer: 18

Step-by-step explanation: Angles opposite of each other in a trapezoid equal 180 minus each other so 180 - 105 = 75 so 75 = 4y + 3

Subtract 3 from both sides

72 = 4y

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8 0
2 years ago
when ashley buys 7 postage stamp booklets she gets 140 stamps.she get 60 stamps in three booklets. write an equation to find the
Andreyy89
We can put this information into two equations:

7 booklets = 140 stamps
3 booklets = 60 stamps

Let us then focus on one equation to find the relationship:

7 booklets = 140 stamps

If we put that into a fraction, we get \frac{7}{140} or \frac{1}{20}.

This means that for every booklet, Ashley gets 20 stamps; or rather, each booklet has 20 stamps.

We can then see that this relationship holds true for the second equation as well:

\frac{3}{60} or \frac{1}{20}.

To write a general equation for this relationship using p for the number of postage stamps, and b for the number of booklets:

p = 20b

Where b is equal to p.
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What is the product (-2a^2+s)(5a^2-6s)
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If the ratio of a circle's sector to its total area is 3/8, what is the measure of its sector's arc?
mars1129 [50]
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Answer:

Solution given:

opposite:9

adjacent: 12

\theta=?

Relationship between opposite and adjacent is given by tan angle

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Tan \theta=\frac{opposite} {adjacent}=\frac{9}{12}

Tan \theta=\frac{3}{4}

\theta=Tan^{-1}\frac{3}{4}

\bold{\theta=36.8°}

#11.

hypotenuse[h]=11cm

opposite/perpendicular[P]=b cm

adjacent/base[b]=a cm

now

\theta=62°

Relationship between height and hypotenuse is given by Sin angle

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Sin 62°=\frac{opposite}{hypotenuse}=\frac{b}{11}

doing crisscrossed multiplication

b=Sin 62°*11

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Relationship between base and hypotenuse is given by Cos angle

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