Answer:
y=4x-4
slope of the line=-4/-1
4/1
since perpendicular,
m1.m2=-1
4.m2=-1
m2=-1/4
The equation of line passing through the point (4,2)is
y-y1=m2(x-x1)
y-2=-1/4(x-4)
Step-by-step explanation:
i don't say that you have to mark my ans as brainliest but my friend if it has helped you a bit also don't forget to thank me.....
I like to use 8 hours of school a day so thats 21 a week but all people are different so at most 36 hours a week
(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ = 
= 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
7h+3s=27.95 subtract 7h from both sides
3s=27.95-7h divide both sides by 3
s=(27.95-7h)/3
Then we are told:
5h+4s=23.4, using s found above makes this equation become:
5h+4(27.95-7h)/3=23.4 multiply both sides by 3
15h+4(27.95-7h=70.2 perform indicated multiplication on left side
15h+111.8-28h=70.2 combine like terms on left side
-13h+111.8=70.2 subtract 111.8 from both sides
-13h=-41.6 divide both sides by -13
h=$3.20
Answer:
£5083
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 2.1%/100 = 0.021 per year,
then, solving our equation
I = 4600 × 0.021 × 5 = 483
I = £ 483.00
The simple interest accumulated
on a principal of £ 4,600.00
at a rate of 2.1% per year
for 5 years is £ 483.00.
