Verify that [tan(theta) + cot(theta)]^2 = sec^2(theta) + csc^2(theta)
1 answer:
(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ = = 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
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Answer:
0.1
Step-by-step explanation:
When Juan cut a 1 lb loaf of banana bread into 6 slices, the weight of each slice forms a repeating decimal. A repeating decimal is a decimal number with repeating digit/s.
i.e = 0.166666666666666...
To express the total weight for each slice, he should write a bar over 6 to show that the number repeats.
i.e = 0.1
Note that has expressed that the division has 6 as the repeating digit in the decimal number.