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PilotLPTM [1.2K]
2 years ago
5

How do I graph these question

Chemistry
1 answer:
USPshnik [31]2 years ago
4 0
Number 1: I think it’s because the air inside of them expands with heat, so you could graph the expansion rate for all of them really
You might be interested in
The infrared spectrum above represents the absorption of certain wavelengths of radiation by molecules of CO2. Which of the foll
valkas [14]

Answer:

Carbon Dioxide is an Infrared Radiation Absorber. The (CO2) molecules also emits the absorbed infrared (IR) radiation energy. The photon energy from the infrared radiation causes the CO2 molecule to vibrate. Only some of its vibrational modes absorb infrared radiation

Explanation:

Its linear structure is considered when working with the formula to calculate the number of molecular vibrational modes. It has 3n - 4 vibrational modes, where n is the number of atoms in a compound of CO2

With 3 atoms, CO2 has

3n−5=4 types or patterns of vibration

1. The symmetric stretch

2. The asymmetric stretch

3. The bend

The symmetric stretch vibrational mode is ir-inactive.

The asymmetric stretch is ir-active as it results in changes in dipole moment

The bend is ir-active as well as it results in a change in dipole moment too.

6 0
3 years ago
When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed?
Ad libitum [116K]

You're looking for the number of moles of H2, and you have 6.0 mol Al and 13 mol HCL.

For the first part, you have to make your way from 6.0 mol of Al to mol of H2, right? For that to happen, you need to make a conversion factor that will cancel the mol Al, in such case use the 2 moles of Al from your equation to cancel them out. At the top of the equation, you can use the number of moles of H2 from the equation and find the moles that will be produced for the H2.

6.0mol Al x 3 mol H2/2 mol Al = 9 mol H2

For the second part, you have to make the same procedure, make a conversion factor that will cancel the mol of HCL and for that you need to use the 6 mol HCL from your equation, and at the numerator you can put the 3 mol of H2 from the equation so that you can find the number of moles of H2 that will be produced.

13 mol HCL x 3 mol H2/6 mol HCL = 6.5 mol H2

As it can be seen, HCL produces the less amount of H2 moles. Therefore, the reaction CANNOT produce more than 6.5 mol H2, in that case 6.5 mol will be the maximum number of moles that will be produced at the end because HCL does not have enough to produce more than 6.5 mol.

In that case HCL is the limiting reactant because it limits that will be produced, and so the answer is B!

6 0
3 years ago
Jonathan is working in his basement on a science fair project when his little sister closes and locks the door. Jonathan wants t
solmaris [256]

Answer:

he can bang metal pipes but i would rather say that he has to yell for help

Explanation:

why because the basement is very loud and echo so when is parents hear him they can run to basement and get him out

hope this helped

4 0
2 years ago
Read 2 more answers
if 30.0L of oxygen are cooled from 200 degrees celsius to 1 degree celsius at constant pressure, what is the new volume of oxyge
Sergio039 [100]

Answer: 18.65L

Explanation:

Given that,

Original volume of oxygen (V1) = 30.0L

Original temperature of oxygen (T1) = 200°C

[Convert temperature in Celsius to Kelvin by adding 273.

So, (200°C + 273 = 473K)]

New volume of oxygen V2 = ?

New temperature of oxygen T2 = 1°C

(1°C + 273 = 274K)

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

30.0L/473K = V2/294K

To get the value of V2, cross multiply

30.0L x 294K = 473K x V2

8820L•K = 473K•V2

Divide both sides by 473K

8820L•K / 473K = 473K•V2/473K

18.65L = V2

Thus, the new volume of oxygen is 18.65 liters.

5 0
2 years ago
Which part of the Periodic Table of the elements is used to identify valence electrons? *
irina1246 [14]
The number of valence electrons of an element can be determined by the periodic table group (vertical column) in which the element is categorized
6 0
2 years ago
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