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Amanda [17]
3 years ago
10

What three things are required for combustion?

Chemistry
2 answers:
SVEN [57.7K]3 years ago
5 0
Heat,oxygen and fuel
PolarNik [594]3 years ago
3 0
Heat , oxygen , fuel hope this helps!
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Write a balanced chemical equation for the complete combustion of C3H7BO3, a gasoline additive. The products of combustion are C
nexus9112 [7]

Answer:

2C₃H₇BO₃ + 8O₂ → 6CO₂ + 7H₂O + B₂O₃.

Explanation:

  • For balancing a chemical equation, we should apply the law of conversation of mass. It states that the no. of atoms in the reactants side is equal to that of the products side.

So, the balanced equation:

<em>2C₃H₇BO₃ + 8O₂ → 6CO₂ + 7H₂O + B₂O₃.</em>

It is clear that 2.0 moles of C₃H₇BO₃ is completely burned in 8 m oles of oxygen and produce 6 moles of CO₂, 7 moles of H₂O and 1 mole of B₂O₃.

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3 years ago
Suppose a giant meteor smashes into the Earth and wipes out the majority of life. Describe how succession would help an ecosyste
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Succession would help over time because new things will appear after
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For part one synthesis reactions The product of the reaction is MgO. Describe what you observed in the reaction then consider th
vazorg [7]

Answer:

2Mg+O_{2} \rightarrow 2MgO

Explanation:

<u>Synthesis reaction:</u>

In the synthesis reaction, two reactants combined to form a single product.

For example,

"A" and "B" are two reactants then combined to form a "AB" product.

The chemical reaction is as follows.

A+B \rightarrow AB

The product "MgO" is formed by magnesium reacts with oxygen to form Magnesium oxide.

The chemical reaction is as follows.

2Mg+O_{2} \rightarrow 2MgO

7 0
3 years ago
9. You have a mini bottle of pure maple syrup. The full container has a mass of 137
cupoosta [38]

Answer:

A

Explanation:EDGE

7 0
3 years ago
How many milliliters of 0.0896M LiOH are required to titrate 25.0 mL of 0.0759M HBr to the equivalence point?
slavikrds [6]

Answer:

V_{LiOH}=21.8mL

Explanation:

Hello,

In this case, during titration at the equivalence point, we find that the moles of the base equals the moles of the acid:

n_{LiOH}=n_{HBr}

That it terms of molarities and volumes we have:

M_{LiOH}V_{LiOH}=M_{HBr}V_{HBr}

Next, solving for the volume of lithium hydroxide we obtain:

V_{LiOH}=\frac{M_{HBr}V_{HBr}}{M_{LiOH}} =\frac{0.0759M*25.0mL}{0.0896M} \\\\V_{LiOH}=21.8mL

Best regards.

8 0
3 years ago
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